$10.50a + $3.75b = $2,071.50
It is given that b = 82
Therefore - $10.50a + ($3.75)(82) = $2,071.50
or $10.50a + $307.50 = $2,071.50
$10.50a = $2,071.50 - $307.50 = $1,764.00
Therefore - a (number of adult tickets sold) = $1,764.00/$10.50 = 168 tickets
Answer:
16
Step-by-step explanation:
The values of x and y are 99 and 343
<h3>The HCF</h3>
The HCF of numbers is the highest common factors of the numbers
<h3>The LCM</h3>
The LCM of numbers is the lowest common multiple of the numbers
The HCF and the LCM are given as:


Multiply the HCF and the LCM


The product of the numbers x and y equals the product of the HCF and the LCM.
So, we have:

<h3>Prime Factors</h3>
Express 33957 as a prime factor

Rewrite the equation as


By comparison:


Hence, the values of x and y are 99 and 343
Read more about HCF and LCM at:
brainly.com/question/420337
Answer:
a. Assume that the population has a normal distribution.
b. The 90% confidence interval of the mean sale time for all homes in the neighborhood is between 219.31 days and 240.69 days.
Step-by-step explanation:
Question a:
We have to assume normality.
Question b:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
That is z with a pvalue of
, so Z = 1.645.
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 230 - 10.69 = 219.31 days.
The upper end of the interval is the sample mean added to M. So it is 230 + 10.69 = 240.69 days.
The 90% confidence interval of the mean sale time for all homes in the neighborhood is between 219.31 days and 240.69 days.