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Helga [31]
3 years ago
15

Jessica and Martha each have a bag of cookies with unequal quantities. They have 30 cookies total between the two of them. Each

of them ate 6 cookies from their bag. The product of the number of cookies left in each bag is not more than 80. How many more cookies will Jessica have Martha? If x represents the number of cookies Jessica started with, complete the statements below.
Mathematics
1 answer:
antiseptic1488 [7]3 years ago
8 0

Answer:

x^2 - 30 + 224 ≥ 0  

the amount of cookies Jessica has more than Martha is at least two

Step-by-step explanation:

J + M = 30

x - 12 < 80

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What is the result of 6 divided by 3/8?<br> Please help I’ll give brainliest
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Step-by-step explanation:

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X and y are both bigger than 30. x and y have HCF 21 and LCM 1617. Find x and y.
Sunny_sXe [5.5K]

The values of x and y are 99 and 343

<h3>The HCF</h3>

The HCF of numbers is the highest common factors of the numbers

<h3>The LCM</h3>

The LCM of numbers is the lowest common multiple of the numbers

The HCF and the LCM are given as:

HCF = 21

LCM = 1617

Multiply the HCF and the LCM

HCF \times LCM = 21 \times 1617

HCF \times LCM = 33957

The product of the numbers x and y equals the product of the HCF and the LCM.

So, we have:

x \times y = 33957

<h3>Prime Factors</h3>

Express 33957 as a prime factor

x \times y = 3^2 \times 7^3 \times 11

Rewrite the equation as

x \times y = 99 \times 7^3

x \times y = 99 \times 343

By comparison:

x = 99

y= 343

Hence, the values of x and y are 99 and 343

Read more about HCF and LCM at:

brainly.com/question/420337

6 0
2 years ago
A family is relocating from St. Louis, Missouri, to California. Due to an increasing inventory of houses in St. Louis, it is tak
Dafna1 [17]

Answer:

a. Assume that the population has a normal distribution.

b. The 90% confidence interval of the mean sale time for all homes in the neighborhood is between 219.31 days and 240.69 days.

Step-by-step explanation:

Question a:

We have to assume normality.

Question b:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645\frac{35}{\sqrt{29}} = 10.69

The lower end of the interval is the sample mean subtracted by M. So it is 230 - 10.69 = 219.31 days.

The upper end of the interval is the sample mean added to M. So it is 230 + 10.69 = 240.69 days.

The 90% confidence interval of the mean sale time for all homes in the neighborhood is between 219.31 days and 240.69 days.

7 0
3 years ago
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