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cupoosta [38]
3 years ago
11

4/5 = ?/10 what is the missing ratio?

Mathematics
2 answers:
blsea [12.9K]3 years ago
7 0
The answer is 8/10 because whatever you do to the first number you do to the second one
romanna [79]3 years ago
7 0
There answer would be 8/10 because the bottom you multiplyed 5*2=10 so you would do 4*2=8
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Can you please help me​
MA_775_DIABLO [31]

Answer:m<c=120

Step-by-step explanation:

You set the two expressions equal to each other solve for x and then plug in x to one expression to get the angle.

After that add the two angles together and subtract them from 360 divide by two and you’ll get the other two angles.


This usually only applies to parallelograms.

I hope this helps it’s been awhile since I’ve done this so if it sounds like gibberish I worked out the problem as a better explanation.

3 0
2 years ago
Sam is planning to take a train 5000km to Seattle. The train wil go at a constanst speed of 2000km/hr.. How long did it take him
Elis [28]

Answer:

2000km=1 hour so 1000km=half an hour (1/2)

5 times half an hour=2.5 hours=2 hours 30 minutes

8 0
2 years ago
Find the nonpermissible replacement for y in the expression y-3/y+3
Nastasia [14]

Answer:

The nonpermissible replacement of the variable y is -3

Step-by-step explanation:

The nonpermissible replacement of the variable in a certain expression is the value of the variable that will make the denominator of the expression zero.

The expression \dfrac{y-3}{y+3} has the denominator y+3.

This denominator cannot be equal zero, thus,

y+3\neq 0,\\ \\y\neq -3.

7 0
3 years ago
Find the range of the data below, 12, 15, 11, 15, 13, 10, 15
morpeh [17]

Answer:5

Step-by-step explanation:

range=greatest number- smallest number

greatest number=15

smallest number=10

range=15-10

range=5

5 0
3 years ago
Is △FHK similar to △GHJ? If so, which postulate or theorem proves these two triangles are similar? ​△FHK​ ​ is similar to ​ ​△GH
blagie [28]

Answer:

ΔFHK and ΔGHJ are the similar triangles by SAS similarity theorem.

Step-by-step explanation:

Picture for the given question is missing; find the picture attached.

If \frac{\text{FH}}{\text{GH}}=\frac{\text{HK}}{\text{HJ}} and ∠H ≅ ∠H

Then ΔFHK ~ ΔGHJ

\frac{\text{FH}}{\text{GH}}=\frac{\text{HK}}{\text{HJ}}

\frac{(12+10)}{10}=\frac{(15+18)}{15}

\frac{22}{10}=\frac{33}{15}

\frac{11}{5}=\frac{11}{5}

Since, \frac{\text{FH}}{\text{GH}}=\frac{\text{HK}}{\text{HJ}} and ∠H ≅ ∠H [By reflexive property]

Therefore, ΔFHK and ΔGHJ are the similar triangles by SAS similarity theorem.

Option (3) will be the answer.

4 0
4 years ago
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