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Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
Answer:
Step-by-step explanation:
(6, 4)
x = 6 and y = 4
y > -1/2x + 7
Plug in the values to check if it is true.
4 > -1/2(6) + 7
4 > -3 + 7
4 > 4
This statement is false.
(6, 4) lies on the line.
We are tasked to solve the three angles given that we have the measurements of the sides such as
a = Zack to Rachel distance
b = Rachel to Maddie distance
c = Maddie to Zack distance
a =3
b =2.5
c =4
Solving the angles we need to use Law of Cosines:
cos A = 2.5² + 4² -3² /2*2.5*4
A = 48.59°
cos B=3² + 4² - 2.5² / 2*3*4
B = 38.625°
C=180 - 48.59° - 38.625°
C= 92.79°
The three angles are 48.59°,38.63° and 92.79°.
Answer:
6.7i + 7.4j
Step-by-step explanation:
if the angle starts from the East (direction of positive x-axis)
then the y (j) component is 10*sin(42) = 6.7
and x (i) component is 10*cos(42) = 7.4
