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frutty [35]
4 years ago
7

It’s been six months since the disk crash at CSM Tech Publishing, and the owner is breathing a little easier because you install

ed a fault-tolerant solution to prevent loss of time and data if a disk crashes in the future. Business is good, and the current solution is starting to run low on disk space. In addition, the owner has some other needs that might require more disk space, and he wants to keep the data on separate volumes (what he calls drives). He wants a flexible solution in which drives and volumes aren’t restricted in their configuration. He also wants to be able to add storage space to existing volumes easily without having to reconfigure existing drives. He has the budget to add a disk storage system that can contain up to 10 HDDs. a. Which Windows feature can accommodate these needs, and how does it work?
Computers and Technology
1 answer:
Semmy [17]4 years ago
5 0

Answer:

Storage Spaces

Explanation:

The feature that would best accommodate his needs would be the Storage Spaces feature that has been implemented in the Windows and Windows Server systems. This feature basically takes various hard drives and combines them together, this ultimately acts as copies of each other which protect the data of each one in the unfortunate case that one of the drives tends to fail. This feature also allows you to add more drives to the existing ones with very minimal effort without restricting configuration. Which would solve the needs that are needed in this scenario.

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Mashcka [7]

Answer:

Font

Explanation:

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3 years ago
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Whats 400000 time 93823
Fynjy0 [20]
Its 375,292,000,00





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7 0
3 years ago
Read 2 more answers
Meg[] elements = {new Lois(), new Stewie(), new Meg(), new Brian()}; for (int i =0; i
Stells [14]

Complete question is attached as snapshot.

Answer:

This will result in a compilation error.

Here's the inheritance hierarchy:

Meg -> Lois -> Brian -> Stewie

Now Meg has 2 public Fxns, a() and toString().

Lois inherits from Meg and all its public functions as well but, overrides the a() fxn of its super class.

So finally Lois has fxns a(), b() and toString().

Brian extends Lois and inherits all the above listed fxns of Lois, but overrides the b() and toString() fxns.

Stewie extends Brian and inherits all the fxns of Brian, but overrides the a() and toString() fxns.

In the Main driver fxn, we call a() and b() methods of all these classes but, the base class Meg has no b() and it is not extending any class so its not available in its scope.

This results in a compilation error.

Explanation:

7 0
3 years ago
11)When, if ever, will the geometric average return exceed the arithmetic average return for a given set of returns?A) When the
grigory [225]

Answer: E. Never

geometric average return can NEVER exceed the arithmetic average return for a given set of returns

Explanation:

The arithmetic average return is always higher than the other average return measure called the geometric average return. The arithmetic return ignores the compounding effect and order of returns and it is misleading when the investment returns are volatile.

Arithmetic returns are the everyday calculation of the average. You take the series of returns (in this case, annual figures), add them up, and then divide the total by the number of returns in the series. Geometric returns (also called compound returns) involve slightly more complicated maths.

6 0
3 years ago
Python
andreyandreev [35.5K]

Answer:

<h2>1)   </h2>

h = 19  # h is already assigned a positive integer value 19

i = 1  # used to calculate perfect square

q = 0   # stores the sum of the perfect squares

while q < h:  

# this loop executes until value of number of perfect squares is less than h

   q = q + (i*i)  # to calculate the sum of perfect squares

   i = i + 1  # increments i by 1 at every iteration

print(q) # displays the sum of perfect squares

Output:

30

Explanation:

Here we see that the sum of the perfect square is printed in the output i.e. 30. If we want to assign value 4 to q then we should alter the code as  following:  

h = 19

i = 1

sum_of_ps = 0

q=0

while sum_of_ps < h:

   sum_of_ps = sum_of_ps + (i*i)

   q = q + 1

   i = i + 1  

print(q)  

If you want to take input from the user and also display the perfect squares in output you can use the following code:

h = int(input('Enter the value of h: ')) #takes value of h from user

i = 1

sum_of_ps = 0

q=0

while sum_of_ps < h:

   sum_of_ps = sum_of_ps + (i*i)

   print(i*i) #displays the perfect squares of h

   q = q + 1

   i = i + 1    

print(sum_of_ps)   #displays sum of perfect squares

print(q) #displays number of perfect squares whose value is less than h

Output:

1

4

9

16

30

4

<h2>2)</h2>

# k and m are already assigned positive integers 10 and 40

k = 10  

m = 40  

i = 1  # i is initialized to 1

q = 0  # q stores the number of perfect squares between k and m

while i*i < m:  # loop computes perfect square of numbers between k and m

   if i*i > k:          

       q = q + 1  # counts the number of perfect squares

   i = i + 1  #increments the value of i at each iteration

print (q) # prints the no of perfect squares between k and m

If you want to display the perfect squares too use , add print(i*i) statement after if statement  if i*i > k:        

Output:

3

<h2>3)</h2>

def Fibonacci(n):  # method Fibonacci which has an integer parameter n

   if n <= 1:  # if the value of n is less than or equals to 1

       result = n  # stores the value of n into result

   elif n > 1:  # else if the value of n is greater than 1

       result = Fibonacci(n-1) + Fibonacci(n-2)  

# calls Fibonacci method recursively to associate nth value of Fibonacci #sequence with variable result

   return result     #returns the final value stored in result variable

print(Fibonacci(8))

#calls Fibonacci function and passes value 8 to it

Output:

21

8 0
3 years ago
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