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2 years ago

X2 - 6x + 12 and y = 2x - 4, algebraically are

Mathematics

1 answer:

olga_2 [115]2 years ago

5 0

The solution is (4, 4)

Solution:

Given system of equations are:

$y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2$

Substitute eqn 2 in eqn 1

$x^2 - 6x + 12 = 2x - 4$

Make the right side of equation 0

$x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0$

Solve by quadratic equation

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4$

Substitute x = 4 in eqn 2

y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

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The cone and the cylinder below have equal surface area. True or false.

WARRIOR [948]

Answer:

False

Step-by-step explanation:

The surface area of the cone is

$V=\pi r^2 +\pi rl$

$SA=\pi r^2 +\pi\times r\times 2r$

$SA=\pi r^2 +2\pi\times r^2$

$SA=3\pi r^2$

The surface area of the cylinder is:

$SA=2\pi r^2 +2\pi rh$

$SA=2\pi r^2 +2\pi\times r\times r$

$SA=4\pi r^2$

3 0

3 years ago

The graph below shows the distance, y, in miles, of a bird from its nest for a certain amount of time, x, in minutes:

Montano1993 [528]

Answer:

$0.2$ miles per minute represents the speed of the bird and 3 miles represents the original distance of the bird from its nest.

Step-by-step explanation:

As there is no graph mentioned here but the information are quite sufficient to answer the question.

We have points $(0,3), (5,4),(10,5)...$

From these points we can find the slope of the line .

From point slope formula $y-y_1=m(x-x_1)$

And assigning $(x,y) (0,3)$ and $(x_1,y_1) (5,4)$

$m=\frac{y_1-y}{x_1-x} =\frac{4-3}{5-0} =\frac{1}{5}=0.2$

This slope is also the speed of the bird which is $0.2\ miles\ per\ minute.$

As by plugging the values of any coordinate point we can confirm this.

Lets put $(10,5)$ , y-axis is the distance so in $10$ minutes the the distance covered by the bird must be equal to to y-axis value which is $5$ miles.