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marusya05 [52]
3 years ago
13

PLEASE HELP NOW!! Will grant brainliest

Mathematics
1 answer:
slava [35]3 years ago
5 0

(f·g)(x) is x^5 - 5x^4 + 4x³ - x² + 5x - 4

Step-by-step explanation:

  • Step 1: Given, f(x) = x² - 5x + 4 and g(x) = x³ - 1 Find (f·g)(x)

(f·g)(x) = f(x)·g(x) = (x² - 5x + 4)(x³ - 1)

                          = x^5 - 5x^4 + 4x³ - x² + 5x - 4

                          = x^5 - 5x^4 + 4x³ - x² + 5x - 4

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Travka [436]
D. All of the above
is the correct answer.

I hope you like this answer and have a good night and life! :D
4 0
2 years ago
Read 2 more answers
Abigail drew a scale drawing of the oldest house in her town. The actual house is 64 feet long. Abigail's scale drawing is 8 inc
cestrela7 [59]

Answer:

1 inch equals 8 feet

Step-by-step explanation:

Given that;

Abigail drew a scale drawing of the oldest house in her town.

The actual  length of the house = 64 feet long

Abigail scale drawing =  8 inches long

The scale he used in drawing the house is determined by choosing a perfect scale:

i.e

If 8 inches is used to draw an actual length of a house which is 64 feet long,

Then 1 inch should be able to draw (64 feet * 1 inch)/ 8 inches

So, 1 inch should be able to draw 8 feet long

4 0
2 years ago
Read 2 more answers
Some body knows how to form a subset?
kipiarov [429]

Answer:

Subset is part of set which is obtained from Universal set.

Step-by-step explanation:

Like for example :-

A - ( 1,2,3,4,5,6,7,8)

And B - ( 1,2 , 3)

So we can say B is subset of A.

5 0
3 years ago
in the lunch room there were 100 chocolate milk cartons at lunch when lunch was over 88 had been purchased
ratelena [41]

Answer:

12 left over 100-88=12

7 0
2 years ago
What is the center of the hyperbola whose equation is (y+3)^2/81-(x-6)^2/89=1?
xxMikexx [17]

We have been given an equation of hyperbola \frac{(y+3)^2}{81}-\frac{(x-6)^2}{89}=1. We are asked to find the center of hyperbola.  

We know that standard equation of a vertical hyperbola is in form \frac{(y-k)^2}{b^2}-\frac{(x-h)^2}{a^2}=1, where point (h,k) represents center of hyperbola.

Upon comparing our given equation with standard vertical hyperbola, we can see that the value of h is 6.

To find the value of k, we need to rewrite our equation as:

\frac{(y-(-3))^2}{81}-\frac{(x-6)^2}{89}=1

Now we can see that value of k is -3. Therefore, the vertex of given hyperbola will be at point (6,-3) and option D is the correct choice.

6 0
3 years ago
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