First lets see how many combinations there are that make 8 from the numbers 1-6:
2+6
3+5
4+4
5+3
and 6+2.
Note: the order does matter, because you roll two die. This means the first die has a number and the second die also has a number. 2 on 1st dice and 6 on 2nd dice would be a different combination than 2 on 2nd dice and 6 on 1st dice.
Now we calculate the probability of getting a number 2 through 6 on the first dice: which is 5/6.
Then calculate the probability of getting a number that pairs up with the first number to make 8: *Note: once you get a number 2 through 6, there is only one other number that you can roll to make 8. This means the probability of getting a match would be 1/6 on the 2nd dice.
Finally, multiply the two fractions we got earlier: 5/6 x 1/6 = 5/36
Your probability would be 5/36 in fraction form, 13.89% in percent form, or 0.139 in decimal form rounded 3 places.
Hope this helps, and May the Force Be With You!
-Jabba the Hut
The solution to the set of equations is (0,2).
Reasoning:
m + 4n = 8 -> 0 + 4(2) = 8
m = n - 2 -> 0 = 2 - 2
The answer is three it is just asking how many times does 15 occur
X intercept = (-3, 0) (3, 0)
y int = (-2,0) (2,0)
I dont get the question so im going to show you both solutions
if you’re asking for (2m+5)²=0 then
(2m+5)²=0 /√
2m+5=0
m=-5/2
if you’re asking only for (2m+5)² then
4m²+20m+25
