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Snezhnost [94]
3 years ago
9

What in simplest form of 12 and 36

Mathematics
1 answer:
Eddi Din [679]3 years ago
3 0
Both can be divided by 12 so 1/3
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WORTH 60 POINTS! PLZ HELP! BRAINLIEST OPPORTUNITY!
makkiz [27]

Answer:

x = 10

Step-by-step explanation:

2) -3x + 17 = -x - 3

4) 20 = 2x

1) -3x + 12 + 5 = -x -3

5) 10 = x

3) 17 = 2x - 3

<u>-3(x - 4) + 5 = -x - 3</u>

<u>-3x + 12 + 5 = -x - 3</u>

<u>-3x + 17 = -x -3</u>

<em>+3x          +3x</em>

<u>17 = 2x - 3</u>

<em>+3        + 3</em>

<u>20 = 2x</u>

<u>10 = x</u>

<u />

I hope that this helps! :)

5 0
3 years ago
a rectangle has an area of 30 square meters and a perimeter of 34 meters. what are the dimensions of the triangle?
gayaneshka [121]
The dimensions for the rectangle are 15 by 2.

15 times 2 is 30, which is the area.

15+15+2+2= 34 which is the perimeter
5 0
3 years ago
(-4,1)and(3,6) Find the slope of the line passing through the pair of points or state that the slope is undefined. Then indicate
Bezzdna [24]

Answer:

The slope is 5/7 and it rises

Step-by-step explanation:

(-4,1) and (3,6)

6 - 1 / 3 - (-4)

5 / 3+4

= 5 / 7

and it rises since the answer is positive

4 0
3 years ago
Read 2 more answers
Please help im so confused
MArishka [77]

Answer:

i

Step-by-step explanation:

i = \sqrt{-1}

i^2 = -1

i^3 = -i

i^4 = 1

(Make sure you know your exponent rules)

i^4^1 = i^4^0 * i = (i^1^0)^4 * i \\i^4 = 1 \\i^1^0 * i *1 \\i^1^0=1\\1*1*i=i

3 0
3 years ago
(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t&lt;00≤t&lt;11≤t&lt;7t≥7;f(t)={0,t&lt;0−5,0≤t&lt;1−6,1≤t&lt;76,t≥7; 1. wr
sergij07 [2.7K]
f(t)=\begin{cases}0&\text{for }t

Recall that

u(t)=\begin{cases}0&\text{for }t

Take it one piece at a time. For t\ge0, we can scale u(t) by -5:

-5u(t)=\begin{cases}0&\text{for }t

If we shift the argument by 1 and scale by -5, we have

-5u(t-1)=\begin{cases}0&\text{for }t

so if we subtract this from -5u(t), we'll end up with

-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t

For the next piece, we can add another scaled and shifted step like

-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t

so that

-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t

For the last piece, we add one more term:

6u(t-7)=\begin{cases}0&\text{for }t

and so putting everything together, we get f(t):

f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)
f(t)\equiv-5u(t)-u(t-1)+12u(t-7)
5 0
3 years ago
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