Answer:
the line perpendicular: x=-3
Step-by-step explanation:
Answer: 2
Explanation: got off math wy in pic
Answer:
the answers (B).
Step-by-step explanation:
IS APEX FOO
The compound interest formula is : 
where, A= Future value including the interest,
P= Principle amount, r= rate of interest in decimal form,
t= number of years and n= number of compounding in a year
Here, in this problem P= $ 51,123.21 , t= 20 years and 2 months
So, t= 20 + (2/12) years
t= 20 + 0.17 = 20.17 years
As the amount is compounded daily, so n= (12×30)= 360 [Using the traditional Banker’s rule of 30 days per month]
Thus, 
When the interest rate is given, then we can use this equation for finding the future value.
Current amount in account
P=36948.61
Future value of this amount after n years at i=11% annual interest
F1=P(1+i)^n
=36948.61(1.11)^n
Future value of $3000 annual deposits after n years at i=11%
F2=A((1+i)^n-1)/i
=3000(1.11^n-1)/0.11
We'd like to have F1+F2=280000, so forming following equation:
F1+F2=280000
=>
36948.61(1.11)^n+3000(1.11^n-1)/0.11=280000
We can solve this by trial and error.
The rule of 72 tells us that money at 11% deposited will double in 72/11=6.5 years, approximately.
The initial amount of 36948.61 will become 4 times as much in 13 years, equal to approximately 147800 by then.
Meanwhile the 3000 a year for 13 years has a total of 39000. It will only grow about half as fast, namely doubling in about 13 years, or worth 78000.
Future value at 13 years = 147800+78000=225800.
That will take approximately 2 more years, or 225800*1.11^2=278000.
So our first guess is 15 years, and calculate the target amount
=36948.61(1.11)^15+3000(1.11^15-1)/0.11
=280000.01, right on.
So it takes 15.00 years to reach the goal of 280000 years.
