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faltersainse [42]
2 years ago
9

I literally don’t get this I need the answer

Mathematics
1 answer:
Ksju [112]2 years ago
6 0

Answer:

62.83 units^{3}

Step-by-step explanation:

The equation is V(Volume) equals π (Pi/3.14) multiplied by r(radius) squared multiplied by h(height). The way it would be written out is V=π×r^{2}×h. So when you plug in the radius (2) and the height (5) you get π×2^{2}×5 which equals 62.83185 or 62.83. I hope this helps you understand and if you need more help let me know.

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6(2x²-5) = [?]<br> x = -3
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6(2(-3)^2-5)

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The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
marusya05 [52]

Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

\hat p =\frac{955-812}{955}= 0.150

0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131

0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169

And the 90% confidence interval would be given (0.131;0.169).

Step-by-step explanation:

We have the following info given:

n= 955 represent the sampel size slected

x = 812 number of students who read above the eighth grade level

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

\hat p =\frac{955-812}{955}= 0.150

The confidence interval for the proportion  would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 90% confidence interval the significance is \alpha=1-0.9=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the normal standard distribution and we got.

z_{\alpha/2}=1.64

And replacing into the confidence interval formula we got:

0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131

0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169

And the 90% confidence interval would be given (0.131;0.169).

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