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Studentka2010 [4]
3 years ago
10

What is the width of a rectangle with an area of 5/8 inches squares and a length of 10 inches.

Mathematics
1 answer:
Ksju [112]3 years ago
5 0
So we are given the area, length and need to find the width
to find the width 
width  = area / length
so to plug in what we know
width = 5/8 divided by 10
width = 1/16 

Hope this helps :)
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What is the equation in vertex form of the quadratic function with a vertex at (-1, -4) that goes through (1, 8)?
cestrela7 [59]

Answer:

y = 3(x+1)^2 - 4

Step-by-step explanation:The general form of the equation of a quadratic function whose vertex is (h,k) and whose leading coefficient is a is:

y - k = a(x-h)^2, or

y      = a(x-h)^2 - k

Substituting the coefficients of the vertex (-1, -4), we get:

y      = a(x + 1)^2 - 4

Substituting the coordinates of the given point, (1,8), we get:

8      = a(1+1)^2 - 4, which simplifies to:

8      = a(2)^2 - 4, or

8  = 4a - 4.  Then 4a = 12, and a = 3.

Thus, the desired equation is y = 3(x+1)^2 - 4 (answer j).


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