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2 years ago

14

What are the coefficients in the problem: 392 + 4x - 5y + x

1 answer:

vovangra [49]2 years ago

4 0

Answer:

the coefficients are 4 and 5 and 1

Step-by-step explanation:

the 4 and 5 have a variable in front of them. There's a ghost 1 in front of the x, because it's value is 1 times whatever the value of x is

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The dot plot below shows how many chocolate chips were in each cookie Lauren brought to school.

Marta_Voda [28]

8+9+10= 27 and 27 divided by 3 is 9. So the mean of the chocolate chips is 9

5 0

2 years ago

Need help Identify three solutions of the graph shown

tester [92]

The solutions are basically the points on the graph that the line passes through. The best way to pick them is to use the whole numbers that are on the corners of the little boxes instead of the middle.

(4, -5)
(3, -3)
(1, 1)
(0, 3)
(-1, 5)
and so on.

6 0

3 years ago

Which is the slope of the line that passes through the points (3,5) and (8,7)?

Hatshy [7]

Hi there!

»»————-　★　————-««

I believe your answer is:

$m=\boxed{\frac{2}{5}}$

»»————-　★　————-««

Here’s why:

The formula for the slope of two given lines given is 'rise over run'.

⸻⸻⸻⸻

$\boxed{\text{Slope Formula:}}\\\\\frac{y_2-y_1}{x_2-x_1}\\\\\rightarrow (x_1,y_1),(x_2,x_1) - \text{Two Points Given}$

⸻⸻⸻⸻

We are given the points (3,5) and (8,7).

⸻⸻⸻⸻

$\boxed{\text{Finding the Slope:}}\\\\\rightarrow m=\frac{7-5}{8-3}\\\\\rightarrow \boxed{m=\frac{2}{5}}$

⸻⸻⸻⸻

»»————-　★　————-««

Hope this helps you. I apologize if it’s incorrect.

7 0

3 years ago

–3(x + 1) ≤ 6 on the number line.

Vladimir [108]

What are u exactly asking

3 0

2 years ago

Find the modulus of the complex number 6-2i

Papessa [141]

Answer:

The modulus of the complex number 6-2i is:

$|z|\:=2\sqrt{10}$

Step-by-step explanation:

Given the number

$6-2i$

We know that

$z = x + iy$

where x and y are real and $\sqrt{-1}=i$

The modulus or absolute value of z is:

$|z|\:=\sqrt{x^2+y^2}$

Therefore, the modulus of $6-2i$ will be:

$z=6-2i$

$z=6+(-2)i$

$|z|\:=\sqrt{x^2+y^2}$

$|z|\:=\sqrt{6^2+\left(-2\right)^2}$

$=\sqrt{6^2+2^2}$

$=\sqrt{36+4}$

$=\sqrt{40}$

$=\sqrt{2^2}\sqrt{2\cdot \:5}$

$=2\sqrt{2\cdot \:5}$

$=2\sqrt{10}$

Therefore, the modulus of the complex number 6-2i is:

$|z|\:=2\sqrt{10}$

3 0

2 years ago