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Vesna [10]
3 years ago
10

The average customer waiting time at a fast food restaurant has been 7.5 minutes. The customer waiting time has a normal distrib

ution. The manager claims that the use of a new system will decrease average customer waiting time in the store. What is the null and alternative hypothesis for this scenario? (Ch10)
A. H0: m =7.5 and H1:m ? 7.5

B. H0: m <=7.5 and H1:m > 7.5

C. H0: m >=7.5 and H1:m < 7.5

D. H0: m <7.5 and H1:m >=7.5

E. H0: m >7.5 and H1:m <= 7.5
Mathematics
1 answer:
tatuchka [14]3 years ago
4 0

Answer: C . H_0:\mu\geq7.5 and H_a:\mu

Step-by-step explanation:

Definition:

Null hypothesis(H_0) is a statement about the population parameter according to the objective raised by the researcher . It contains '=' , '≤' and  '≥' signs.

Alternative hypothesis(H_a) is also a statement about the population parameter but against null hypothesis  . It contains '≠' , '<' and  '>' signs.

Let \mu be the average customer waiting time for the population.

Given : The average customer waiting time at a fast food restaurant has been 7.5 minutes.

Objective of test : After using new system ,  the average customer waiting time is at least 7.5 or less than 7.5.

Then, the null and alternative hypothesis for this scenario will be :

H_0:\mu\geq7.5

H_a:\mu

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Answer:

12

i think

Step-by-step explanation:

4 0
3 years ago
The accompanying data contains the depth​ (in kilometers) and​ magnitude, measured using the Richter​ Scale, of all earthquakes
Sunny_sXe [5.5K]

Answer:

Depth:

μ =20.2025 km

M = 15.625 km

Range = 47.15 km

σ ≈ 15.92 km

Q₁ = 5.7375 km

Q₃ =  34.6675 km

Magnitude:

μ = 2.08375

M = 1.465

Range, R = 5.17

σ = 1.801485 ≈ 1.8

Q₁ = 0.5625

Q₃ = 3.925

Step-by-step explanation:

The given data are;

Depth {}                                 Magnitude

0.76 {}                                    0.84

4.93 {}                                    0.47

8.16 {}                                     0.35

33.58 {}                                  1.32

21.2 {}                                     1.61

35.03 {}                                  4.57

10.05 {}                                   5.52

47.91 {}                                    1.99

For the Depth, we have;

The mean, μ = (0.76+4.93+8.16+33.58+21.2+35.03+10.05+47.91)/8 =20.2025 km

The median, M = The (n + 1)/2th term after arranging the term in increasing order as follows;

0.76, 4.93, 8.16, 10.05, 21.2, 33.58, 35.03, 47.91 , the median is therefore;

(8 + 1)/2th term or the 4.5th term which is 10.05 + (21.2 - 10.05)/2 = 15.625 km

The Range = The highest - The lowest value = 47.91 - 0.76 = 47.15 km

The Standard deviation of, σ, is given as follows;

\sigma =\sqrt{\dfrac{\sum \left (x_i-\mu  \right )^{2} }{N}}

Where;

x_i = The individual data point = (0.76, 4.93, 8.16, 10.05, 21.2, 33.58, 35.03, 47.91 )

N = The total number of data point = 8

Substituting, (using Microsoft Excel) we get;

\sigma =\sqrt{\dfrac{\sum \left (x_i-20.2025  \right )^{2} }{8}} \approx 15.92 \ km

Q₁ = The first quartile = The (n + 1)/4th =  term arranged in increasing order

Q₁ = The (8 + 1)/4th term = The 2.25th term = 4.93 + (8.16 - 4.93)×0.25) = 5.7375 km

Q₃ = The first quartile = The 3×(n + 1)/4th =  term arranged in increasing order

Q₃ = The 3×(8 + 1)/4th term = The 6.75th term = 33.58 + 3×(35.03 - 33.58)×0.25) = 34.6675 km

For the magnitude, we have, using the same formulas and procedures as above;

μ = 2.08375

M = 1.465

Range, R = 5.17

σ = 1.801485 ≈ 1.8

Q₁ = 0.5625

Q₃ = 3.925

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3 years ago
How do I solve for x?
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Solving:
\frac{3+4x}{2} + \frac{5-x}{3} = \frac{29}{6}
Make the Least Common Multiple (2,3,6)
2,3,6\:|2
1,3,3\:|3
1,1,1\:|\underline{2*3=6}


<span>Replace denominators and resolve:
</span>\frac{3+4x}{2} + \frac{5-x}{3} = \frac{29}{6}
\frac{3(3+4x)}{6} + \frac{2(5-x)}{6} = \frac{29}{6}
Cancel the dominators
\frac{3(3+4x)}{\diagup\!\!\!\!6} + \frac{2(5-x)}{\diagup\!\!\!\!6} = \frac{29}{\diagup\!\!\!\!6}
3(3+4x) + 2(5-x) = 29
9 + 12x + 10 - 2x = 29
12x - 2x = 29 - 9 - 10
10x = 20 - 10
10x = 10
x =  \frac{10}{10}
\boxed{\boxed{x = 1}}\end{array}}\qquad\quad\checkmark


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3 years ago
A number x divided by 3 is at most 5 An inequality that represents this word sentence is
svet-max [94.6K]

Answer:

x/3 ≥ 5

Step-by-step explanation:

4 0
3 years ago
Find the discriminant of the following equation.<br> 4x2 + 16x + 16 = 0 ...?
kenny6666 [7]

Discriminant = b^2 - 4ac

a = 4

b = 16

c = 16

16^2 - 4(4 x 16)

256 - (4x64)

256 - 256 = 0

Therefore it only has one root

7 0
3 years ago
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