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Serjik [45]
2 years ago
9

Maria is planning to attend UCLA. She is curious what the average age of UCLA students is. Since most students that attend UCLA

are in their 20’s yet there are also students up to 70 years old, the population is positively skewed. The college conducted a random sample of 65 students and found that the sample mean was 29.0 years old with a standard deviation of 5.2 years. Does this data meet the assumptions necessary to perform a hypothesis test? If so, use a 10% significance level to test the claim that the average age of students at UCLA is 30 years old.
Mathematics
1 answer:
RoseWind [281]2 years ago
8 0

Answer:

Yes

We fail to reject the alternative hypothesis Hₐ < 30, that is the average age of students is less than 30

Step-by-step explanation:

Yes because, there is an average age of a sample which can be tested against a null hypotheses

We put

Null hypothesis as H₀ = 30

The alternative hypothesis as Hₐ < 30

We have

z=\frac{\bar{x}-\mu }{\frac{\sigma }{\sqrt{n}}}

With

\bar x = 29

μ = 30

σ = 5.2

n = 65

α = 10%

We have

Here we have z = -1.55 and critical z = -1.28

Which gives a critical \bar x of 29.83 with the probability P = 0.061 < 0.1 Hence we reject the null hypothesis as there is sufficient evidence to suggest that the average age is less than 30 years.

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Find the volume of a regular hexahedron if one of the diagonals of its faces is 8 root 2 inches.
Naily [24]
The answer is 114sqrt{6} in³

A regular hexahedron is actually a cube. 

Diagonal of a cube D is a hypotenuse of a right triangle which other two legs are face diagonal (f) and length of a side (a):
D² = f² + a²

Face diagonal is a hypotenuse of a right triangle which sides are a and a:
f² = a² + a² =2a²

D² = f² + a²
f² = 2a²

D² = 2a² + a² = 3a²
D = √3a² = √3 * √a² = √3 * a = a√3

Volume of a cube with side a is: V = a³
D = a√3
⇒ a = D/√3

V = a³ = (D/√3)³

We have:
D = 8√2 in

V= (\frac{D}{ \sqrt{3} } )^{3} =( \frac{8 \sqrt{2} }{ \sqrt{3} } )^{3}=( \frac{8 \sqrt{2} * \sqrt{3} }{ \sqrt{3}* \sqrt{3}} )^{3} =( \frac{8 \sqrt{2*3} }{ \sqrt{3*3}} )^{3} =( \frac{8 \sqrt{6} }{ \sqrt{3^{2} }} )^{3} =( \frac{8 \sqrt{6} }{ 3} )^{3} = \\ \\ = \frac{ 8^{3} *( \sqrt{6} )^{3}}{3^{3}} = \frac{512* \sqrt{6 ^{2} }* \sqrt{6} }{27} = \frac{512*6* \sqrt{6} }{27} = 114sqrt{6}
8 0
3 years ago
The work that Yi did to find the greatest common factor of 42 and 63
Lilit [14]

Answer:

21

Step-by-step explanation:

factors of 42: 1,42, 2,<u>21</u>, 3,14, 6,7

factors of 63: 1,63, 3,<u>21</u>, 7,9

7 0
3 years ago
Using complete sentences, discuss the different kinds of real numbers. In your answer, glve an example of each type and discuss
Nadya [2.5K]

Answer:

Different type of real numbers include natural numbers, whole numbers, integers, irrational numbers, and rational numbers. Natural numbers are the set of numbers (1, 2, 3, 4...) also known as counting numbers. Whole numbers are natural numbers including zero (0, 1, 2, 3, 4...). Integers are the set of whole numbers and their opposites (-3, -2, -1, 0, 1, 2, 3...). Irrational numbers are numbers that cannot be expressed as a ratio of two integers. Their decimal expansions are nonending and nonrepeating. An example of an irrational number is pi (3.14). A rational number is a number that can be written as a fraction. It includes integers, terminating decimals, and repeating decimals. An example of a rational number is the number 214.

Step-by-step explanation:

7 0
3 years ago
Please help me!!! will mark brainlest
Licemer1 [7]

A. To be able to have the 2 sides ( the 2 triangles) line up correctly, Net A would be the correct one.


B. AB = 3

BC = 5

CD = 9.4



C. Surface area:

9.4 x 5 = 47

9.4 x 3 = 28.2

9.4 x 4 = 37.6

3 x 4 = 12


Total: 47 + 28.2 + 37.6 + 12 = 124.8 sq. in.

8 0
3 years ago
The Ohio Department of Agriculture tested 203 fuel samples across the state in 1999 for accuracy of the reported octane level. F
OlgaM077 [116]

Answer:

The Sample size is 1918.89035

Step-by-step explanation:

Consider the provided information.

It is given that 14 out of 105 samples failed.

Therefore p = 14/105 = 0.13 3... and q=1-0.133=0.867

Samples would be needed to create a 99 percent confidence interval.

Subtract the confidence level from 1, then divide by two.

\frac{(1 -0.99)}{2}=0.005

By standard normal table z=2.5758≈2.58

Calculate the sample size as:

n=\frac{z^2pq}{e^2}

Where,  e is the margin of error,

Substitute the respective values.

n=\frac{(2.58)^2(0.133)(0.867)}{(0.02)^2}=1918.89

Hence, the Sample size is 1918.89035

4 0
3 years ago
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