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Slav-nsk [51]
3 years ago
7

Find x. A. 4/6 B. 6 c. 4√3 D.3/2

Mathematics
1 answer:
lubasha [3.4K]3 years ago
7 0
The answer is b sorry if I’m incorrect though
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Select the expression that represents the following statement: 52 minus 4 times the difference of 13 and 7.
vampirchik [111]

Answer:

(52 - 4) * (13 - 7)

Step-by-step explanation:

<u>Step 1:  Convert words into an expression</u>

52 minus 4 times the difference of 13 and 7.

(52 - 4) * (13 - 7)

Answer:  (52 - 4) * (13 - 7)

If needed simplify

(52 - 4) * (13 - 7)

48 * 6

288

6 0
3 years ago
Carter has 193 songs on a playlist. He's categorized them in the following manner: 39 pop. 17 jazz. 33 Latin American, 10 countr
Lorico [155]

Step-by-step explanation:

Total songs = 193

Probability of pop song = 39/193 = 0.202

7 0
3 years ago
A string of a kite is 100 meters long and it makes an angle of 60° with horizontal. Find the height of the kite and then find th
MAXImum [283]

Answer:

Height of the kite is =50 \sqrt{3} meters.

Ground distance from the kite to the person flying the kite is 50 meters.

Step-by-step explanation:

Given that a string of a kite is 100 meters long and it makes an angle of 60° with horizontal.

Which mans we are getting a shape of right angle triangle as shown in picture. Where "y" is the height of the kite and "x" is the ground distance from the kite to the person flying the kite. Now we can use trigonometric ratios to find the values of x and y.


\sin\left(60^o\right)=\frac{\left[opposite\right]}{\left[hypotenuse\right]}=\frac{y}{100}

\sin\left(60^o\right)=\frac{y}{100}

\frac{\sqrt{3}}{2}=\frac{y}{100}

\frac{\sqrt{3}}{2}*100=y

50 \sqrt{3}=y

Hence height of the kite is =50 \sqrt{3} meters.


similarly:


\cos\left(60^o\right)=\frac{\left[adjcent\right]}{\left[hypotenuse\right]}=\frac{x}{100}

\cos\left(60^o\right)=\frac{x}{100}

\frac{1}{2}=\frac{x}{100}

\frac{1}{2}*100=x

50=x

Hence ground distance from the kite to the person flying the kite is 50 meters.


6 0
3 years ago
Keith is racing his little sister Pattie and has given her a 15 foot head start. She runs 5ft/sec and he is chasing at 8ft/sec.
hodyreva [135]
Pattie runs at 5 ft/sec
She has got a head start of 15 feet.
So after 1 second, Pattie runs = (5+15) ft <span>                                                   
                                                  = 20 </span> ft
After 2 second Pattie runs = (20+5)ft
                                           = 25 ft
After 3 second Pattie runs = (25+5) ft
                                           = 30 ft
After 4 seconds Pattie runs = (30+5) ft
                                             = 35 ft
After 5 seconds Pattie runs = (35+5) ft
                                             = 40 ft
After 6 seconds Pattie runs  = (40+5) ft
                                             = 45 ft
Now Keith runs at 8 ft/sec
After 1 second Keith runs = 8 ft
After 2 second Keith runs = (8+8) ft
                                           = 16 ft
After 3 second Keith runs = (16+8) ft
                                           = 24 ft
After 4 second Keith runs = (24+8) ft
                                          = 32 ft
After 5 second Keith runs = (32+8) ft
                                           = 40 ft
After 6 second Keith runs = (40+8) ft
                                           = 48 ft
So Pattie will stay ahead of Keith upto 4 seconds. In the 5th second Pattie and Keith will be level and in the 6th second Pattie will be overtaken by Keith.


8 0
3 years ago
Solve for x.<br><br> −15(x−4)=−2
-BARSIC- [3]

Answer:

x = 62/15

Step-by-step explanation:

explenation on picture :))

6 0
3 years ago
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