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3 years ago

Wich x makes the statement 7+5 (x-3)=22 a true statement (URGENT)

Mathematics

1 answer:

julsineya [31]3 years ago

4 0

Answer:

The answer would be C.) x = 6

Step-by-step explanation:

7+5 (4-3) = 12

7+5 (5 -3) = 17

7+5 (6-3) = 22

7+5 (7-3) = 27

You might be interested in

A taste test asks people from Texas and California which pasta they prefer,

melamori03 [73]

Answer:

Yes, they are independent because P(Texas) ≈ 0.45 and P(Texas/brand A) ≈ 0.45.

Step-by-step explanation:

We are given that a taste test asks people from Texas and California which pasta they prefer, brand A or brand B. The table is given in the question.

A person is randomly selected from those tested.

And we have find that are being from Texas and preferring brand A independent events or not.

Firstly, we know that these two events will be independent when;

P(Texas) = P(Texas/brand A)

Now, P(Texas) = $\frac{\text{Number of people from Texas}}{\text{Total number of people}}$

= $\frac{125}{275}$ ≈ 0.45

Also, P(Texas/brand A) = $\frac{P(Texas \bigcap Brand A)}{P(Brand A)}$

= $\frac{\text{Number of people from Texas and preferring brand A}}{\text{Number of people preferring brand A}}$

= $\frac{80}{176}$ ≈ 0.45

Therefore, being from Texas and preferring brand A are independent events because P(Texas) ≈ 0.45 and P(Texas/brand A) ≈ 0.45.

6 0

2 years ago

Five cards are drawn from a standard 52-card playing deck. A gambler has been dealt five cards—two aces, one king, one 3, and on

Nookie1986 [14]

Answer:

The probability that he ends up with a full house is 0.0083.

Step-by-step explanation:

We are given that a gambler has been dealt five cards—two aces, one king, one 3, and one 6. He discards the 3 and the 6 and is dealt two more cards.

We have to find the probability that he ends up with a full house (3 cards of one kind, 2 cards of another kind).

We know that gambler will end up with a full house in two different ways (knowing that he has given two more cards);

If he is given with two kings.
If he is given one king and one ace.

Only in these two situations, he will end up with a full house.

Now, there are three kings and two aces left which means at the time of drawing cards from the deck, the available cards will be 47.

So, the ways in which we can draw two kings from available three kings is given by = $\frac{^{3}C_2 }{^{47}C_2}$ {∵ one king is already there}

= $\frac{3!}{2! \times 1!}\times \frac{2! \times 45!}{47!}$ {∵ $^{n}C_r = \frac{n!}{r! \times (n-r)!}$ }

= $\frac{3}{1081}$ = 0.0028

Similarly, the ways in which one king and one ace can be drawn from available 3 kings and 2 aces is given by = $\frac{^{3}C_1 \times ^{2}C_1 }{^{47}C_2}$

= $\frac{3!}{1! \times 2!}\times \frac{2!}{1! \times 1!} \times \frac{2! \times 45!}{47!}$

= $\frac{6}{1081}$ = 0.0055

Now, probability that he ends up with a full house = $\frac{3}{1081} + \frac{6}{1081}$

= $\frac{9}{1081}$ = <u>0.0083</u>.

3 0

3 years ago

Read 2 more answers

??????????????????????

I am Lyosha [343]

The answer is A. Closure

6 0

2 years ago

What is the value of x? <br>

kiruha [24]

Answer:

lj= lk din 30 give lj= 4✓2

and ml=x= lj cos 45

on solving x= 4✓2 cos45=4

8 0

2 years ago

The lowest number is 11 the range is 13 and the median is 17 what are the 3 numbers

11Alexandr11 [23.1K]

Answer:

11, 17, and 28.

Step-by-step explanation:

$x, y, z\\$

Lowest number is $x$

Median is $y$

Highest number is $z$

$x=11\\y=17\\\\z-x=17\\z-11=17\\z-11+11=17+11\\z=28\\\\x=11\\y=17\\z=28\\\\11, 17, 28$

3 0

3 years ago