Ask question

Ask question

All categories

3 years ago

14

Please help me with this

1 answer:

TEA [102]3 years ago

5 0

Answer:

6y

Step-by-step explanation:

The two figure are squares with the same area

side = √area = √y^2 = y (with y>0 because a length can‘t be negative)

perimeter = side * 6 = y * 6 = 6y

You might be interested in

Which rule describes the translation?

max2010maxim [7]

Answer:

c

Step-by-step explanation:

translations assignment

4 0

3 years ago

Consider the sequence:

Vera_Pavlovna [14]

Answer:

a_n = 2^n + 3

Step-by-step explanation:

The first differences have a geometric progression, so the explicit definition will be an exponential function. (It cannot be modeled by a linear or quadratic function.) The above answer is the only choice that is an exponential function.

__

First differences are ...

(7-5=)2, 4, 8, 16

8 0

3 years ago

Read 2 more answers

Select TWO values of x that are roots

Sauron [17]

$x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a};\ x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\y=x^2+3x+5\\\\a=1;\ b=3;\ c=5\\\\b^2-4ac=3^2-4(1)(5)=9-20=-11\\\\x_1=\dfrac{-3-\sqrt{-11}}{2\cdot1}=\dfrac{-3-\sqrt{-11}}{2}\\\\x_2=\dfrac{-3+\sqrt{-11}}{2}$

Answer: A and B.

3 0

3 years ago

Read 2 more answers

In 2002, there were 972 students enrolled at Oakview High School. Since then, the number of students has increased by 1.5% each

Rudiy27

Answer:

$N(t) = 972(1.015)^{t}$

Growth function.

The number of students enrolled in 2014 is 1162.

Step-by-step explanation:

The number of students in the school in t years after 2002 can be modeled by the following function:

$N(t) = N(0)(1+r)^{t}$

In which N(0) is the number of students in 2002 and r is the rate of change.

If 1+r>1, the function is a growth function.

If 1-r<1, the function is a decay function.

In 2002, there were 972 students enrolled at Oakview High School.

This means that $N(0) = 972$

Since then, the number of students has increased by 1.5% each year.

Increase, so r is positive. This means that $r = 0.015$

Then

$N(t) = N(0)(1+r)^{t}$

$N(t) = 972(1+0.015)^{t}$

$N(t) = 972(1.015)^{t}$

Growth function.

Find the number of students enrolled in 2014.

2014 is 2014-2002 = 12 years after 2002, so this is N(12).

$N(t) = 972(1.015)^{t}$

$N(12) = 972(1.015)^{12}$

$N(12) = 1162$

The number of students enrolled in 2014 is 1162.

7 0

3 years ago

Solve for m: 18d − 2m + 9k < 5k + 10

snow_tiger [21]

$18d-2m+9k$ < $5k+10$

$18d-2m$ < $-4k +10$

$-2m$ < $-4k +10 -18d$

$m$ > $\frac{-4k+10-18d}{-2}$ (flipped the sign because we're dividing by a negative)

$m$ > $2k+5+9d$

4 0

3 years ago

Read 2 more answers