If no base is stated, then assume base 10
![log(x)=log_{10}(x)](https://tex.z-dn.net/?f=log%28x%29%3Dlog_%7B10%7D%28x%29)
rememer
![a=log_b(c)](https://tex.z-dn.net/?f=a%3Dlog_b%28c%29)
translates to
![b^a=c](https://tex.z-dn.net/?f=b%5Ea%3Dc)
so
![r=log(x)](https://tex.z-dn.net/?f=r%3Dlog%28x%29)
or
![r=log_{10}(x)](https://tex.z-dn.net/?f=r%3Dlog_%7B10%7D%28x%29)
translates to
![10^r=x](https://tex.z-dn.net/?f=10%5Er%3Dx)
so when r=7.9, what is x
![10^r=x](https://tex.z-dn.net/?f=10%5Er%3Dx)
![10^{7.9}=x](https://tex.z-dn.net/?f=10%5E%7B7.9%7D%3Dx)
79432823.472428=x
round to nearest ???
thousanth? 79432823.472=x
hundreth? 79432823.47=x
tenth? 79432823.5=x
![= 2x = \frac{1}{8 } \\ = x = \frac{1}{2 \times 8} \\ = x = \frac{1}{16}](https://tex.z-dn.net/?f=%20%3D%202x%20%3D%20%20%5Cfrac%7B1%7D%7B8%20%7D%20%20%5C%5C%20%20%3D%20x%20%3D%20%20%5Cfrac%7B1%7D%7B2%20%5Ctimes%208%7D%20%20%5C%5C%20%20%3D%20x%20%3D%20%20%5Cfrac%7B1%7D%7B16%7D%20)
![3x \times 9 = 81 \\ 3x = \frac{81}{9} \\ x = \frac{9}{3} \\ x = 3](https://tex.z-dn.net/?f=3x%20%5Ctimes%209%20%3D%2081%20%5C%5C%203x%20%3D%20%20%5Cfrac%7B81%7D%7B9%7D%20%5C%5C%20x%20%3D%20%20%5Cfrac%7B9%7D%7B3%7D%20%20%5C%5C%20%20x%20%3D%203)
Heres your answer girlfriend ♥️♥️
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