The possible digits are:
5, 6, 7, 8 and
9. Let's mark the case when the locker code begins with a prime number as
A and the case when <span>the locker code is an odd number as
B. We have
5 different digits in total,
2 of which are prime (
5 and
7).
First propability:
</span>

<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with
5, 7 or
9 (three of five digits).
Second probability:
</span>
Answer:
16
Step-by-step explanation:
First you want to plug in all the numbers where the letters are
h ( j + i )- k(5) + h
3 ( 2 + 4 )- 1(5) + 3
After this step you will have to distribute the 3 outside the parenthesis. Which you do by multiplying everything in side the parenthesis by the outside number which is three.
6 + 12 - 1(5) + 3
Then you just follow PEMDAS to solve for the rest
6 + 12 - 5 + 3
18 - 5 + 3
13 + 3
16
Answer:
8 batches
Step-by-step explanation:
divide 5 1/3 and 2/3
Hope this helps