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3 years ago

3. Shawna's Bikes rents bikes for $19 plus $4 per hour. Lea paid $39 to rent a bike. For how many hours did she rent the bike?

Mathematics

2 answers:

noname [10]3 years ago

6 0

Lea rented the bike for 5 hours.

mote1985 [20]3 years ago

3 0

19 -34 =15 15 divided by 4 = 3.75 which is three hours and 30 minutes

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3 years ago

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-2x-2+x^2+x+180+-2x-2=180

Dominik [7]

Answer:

x= 4, -1

Step-by-step explanation:

-2x - 2 + x^2 + x + 180 - 2x - 2 = 180

add like terms and put in descending order

x^2 - 3x + 176 = 180

subtract 180 from both sides

x^2 - 3x - 4 = 0

factor out the equation

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5 0

3 years ago

Jonathan bought a table and some chairs at a furniture store.

Naily [24]

Answer:

It must be the cost of the one table.

Step-by-step explanation:

It's logic. 25x is the cost of the (unknown) number of chairs.

The total Amount he spent is the cost of the chairs <u>plus</u> what he spent on the table.

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3 years ago

What is the solution to this system of linear equations?

timurjin [86]

B is the answer to your question

7 0

3 years ago

A company manufactures running shoes and basketball shoes. The total revenue (in thousands of dollars) from x1 units of running

Alborosie

Answer:

$x_1 =2 , x_2=7$

Step-by-step explanation:

Consider the revenue function given by $R(x_1,x_2) = -5x_1^2-8x_2^2 -2x_1x_2+34x_1+116x_2$ . We want to find the values of each of the variables such that the gradient( i.e the first partial derivatives of the function) is 0. Then, we have the following (the explicit calculations of both derivatives are omitted).

$\frac{dR}{dx_1} = -10x_1-2x_2+34 =0$

$\frac{dR}{dx_2} = -16x_2-2x_1+116 =0$

From the first equation, we get, $x_2 = \frac{-10x_1+34}{2}$ .If we replace that in the second equation, we get

$-16\frac{-10x_1+34}{2} -2x_1+116=0= 80x_1-2x_1+116-272= 78x_1-156$

From where we get that $x_1 = \frac{156}{78}=2$ . If we replace that in the first equation, we get

$x_2 = \frac{-10\cdot 2 +34}{2}=\frac{14}{2} = 7$

So, the critical point is $(x_1,x_2) = (2,7)$ . We must check that it is a maximum. To do so, we will use the Hessian criteria. To do so, we must calculate the second derivatives and the crossed derivatives and check if the criteria is fulfilled in order for it to be a maximum. We get that

$\frac{d^2R}{dx_1dx_2}= -2 = \frac{d^2R}{dx_2dx_1}$

$\frac{d^2R}{dx_{1}^2}=-10, \frac{d^2R}{dx_{2}^2}=-16$

We have the following matrix,

$\left[\begin{matrix} -10 & -2 \\ -2 & -16\end{matrix}\right]$ .

Recall that the Hessian criteria says that, for the point to be a maximum, the determinant of the whole matrix should be positive and the element of the matrix that is in the upper left corner should be negative. Note that the determinant of the matrix is $(-10)\cdot (-16) - (-2)(-2) = 156>0$ and that -10<0. Hence, the criteria is fulfilled and the critical point is a maximum

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3 years ago

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