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kherson [118]
3 years ago
7

Angles α and β are the two acute angles in a right triangle. Use the relationship between sine and cosine to find the value of β

if β < α. sin( x/2 + 2x) = cos(2x + 3x/2 )
A) 15°

B) 37.5°

C) 52.5°

D) 75°
Mathematics
1 answer:
Dimas [21]3 years ago
7 0

Answer:

From given relation the value of β is 37.5°

Step-by-step explanation:

Given as :

α and β are two acute angles of right triangle

Acute angle have measure less than 90°

Now given as :

sin(\frac{x}{2} + 2x) = cos(2x +\frac{3x}{2})

Or, cos(90° - (\frac{x}{2}+2x)) =  cos(2x +\frac{3x}{2})

SO, (90° - (\frac{x}{2}+2x)) = 2x+\frac{3x}{2}

Or, 90° =  2x+\frac{3x}{2} + \frac{x}{2}+2x

or, 90° = \frac{4x}{2} + 4x

Or,  90° =  \frac{12x}{2}

So, x =  \frac{90}{6} = 15°

∴ sin(\frac{x}{2} + 2x) = sin(\frac{15}{2} + 30)

So, sin(\frac{x}{2} + 2x) = sin\frac{75}{2}

∴  The value of Ф_1 = \frac{75}{2} = 37.5°

Similarly  cos(2x +\frac{3x}{2}) =  cos(30 +\frac{45}{2})

So ,The value of Ф_2 = \frac{105}{2} = 52.5°

∵ β   α

So, As 37.5°52.5°

∴ β = 37.5°

Hence From given relation the value of β is 37.5°  Answer

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