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2 years ago

What digits are the thousands period 9,827,273

2 answers:

8 0

If you are talking about hundred thousands, ten thousands and thpusands then the second, third and fourth but if your just talking about thousands then it's just the fourth.

statuscvo [17]2 years ago

7 0

The digits in the thousands period on 9827273 are 8 2 and 7

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Solve the equation.round to the nearest thousandths -5+2in(3x)=5

Crank

What is the "in" for in your equation? Repost.

6 0

2 years ago

Scores on a final exam taken by 1200 students have a bell shaped distribution with mean=72 and standard deviation=9

SVETLANKA909090 [29]

Answer:

a. 72

b. 816

c. 570

d. 30

Step-by-step explanation:

Given the graph is a bell - shaped curve. So, we understand that this is a normal distribution and that the bell - shaped curve is a symmetric curve.

Please refer the figure for a better understanding.

a. In a normal distribution, Mean = Median = Mode

Therefore, Median = Mean = 72

b. We have to know that 68% of the values are within the first standard deviation of the mean.

i.e., 68% values are between Mean $\pm$ Standard Deviation (SD).

Scores between 63 and 81 :

Note that 72 - 9 = 63 and

72 + 9 = 81

This implies scores between 63 and 81 constitute 68% of the values, 34% each, since the curve is symmetric.

Now, Scores between 63 and 81 = $\frac{68}{100} \times 1200$

= 68 X 12 = 816.

That means 816 students have scored between 63 and 81.

c. We have to know that 95% of the values lie between second Standard Deviation of the mean.

i.e., 95% values are between Mean $\pm$ 2(SD).

Note that 90 = 72 + 2(9) = 72 + 18

Also, 54 = 63 - 18.

Scores between 54 and 90 totally constitute 95% of the values. So, Scores between 72 and 90 should amount to $\frac{95}{2} \%$ of the values.

Therefore, Scores between 72 and 90 = $\frac{95}{2(100)} \times 1200 = \frac{95}{200} \times 1200$

$\implies 95 \times 12$ = 570.

That is a total of 570 students scored between 72 and 90.

d. We have to know that 5 % of the values lie on the thirst standard Deviation of the mean.

In this case, 5 % of the values lie between below 54 and above 90.

Since, we are asked to find scores below 54. It should be 2.5% of the values.

So, Scores below 54 = $\frac{2.5}{100} \times 1200$

= 2.5 X 12 = 30.

That is, 30 students have scored below 54.

8 0

2 years ago

12)

Jlenok [28]

Answer:

Ato find the vertex

Step-by-step explanation:

6 0

2 years ago

Bethany is making cookies for her friend. If it takes her 15 minutes to make 3 dozen, how long will it take her to make 6 dozen

Katyanochek1 [597]

If three dozens took 15 minutes that five minutes a dozen and with six dozens it would be 30 minutes

7 0

3 years ago

A population of squirrels on an island has a carrying capacity of 350 individuals. If the maximum rate of increase is 1.0 per in

TiliK225 [7]

Answer:

The population growth rate is 59 squirrels per year.

Step-by-step explanation:

Given:

A population of squirrels on an island has a carrying capacity of 350 individuals. If the maximum rate of increase is 1.0 per individual per year and the population size is 275.

Now, to find the population growth rate.

Carrying capacity ( $K$ ) = 350.

Maximum rate ( $r_{max}$ ) = 1.0 per individual per year.

Population size ( $N$ ) = 275.

Now, to get the population growth rate we put formula:

$\frac{dN}{dT}= r_{max}\frac{K-N}{K}N$

$\frac{dN}{dT}=1.0\times \frac{350-275}{350}\times 275\\\\\frac{dN}{dT}=1.0\times \frac{75}{350}\times 275\\\\\frac{dN}{dT}=1.0\times 0.214\times 275\\\\\frac{dN}{dT}=58.85.$

So, rounding to nearest whole number of the population growth rate is 59 squirrels per year.

Therefore, the population growth rate is 59 squirrels per year.

6 0

2 years ago