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2 years ago

How can you represent real world situations using positive nubers, negative nubers, and zero?

1 answer:

Natasha2012 [34]2 years ago

6 0

Answer:Maybe ffor the positive numbers you could use like 1,2,3,4,5,6,7,8, and 9. For the negitive number could be like -1,-2,-3,-4,-5. And zero could repersent the middle. Get it or no?

Step-by-step explanation:

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Help me on this please

Rina8888 [55]

Answer:

x = 3.5

Step-by-step explanation:

Triangle to the right:

4^2 + x^2 = 8^2

16 + x^2 = 64

y^2 = 48

Triangle to the left:

x^2 + 6^2 = 48

x^2 + 36 = 48

x^2 = 12

x = sqrt(12)

x = 3.5

4 0

2 years ago

Help please :) ill give brainliest to correct answer.

aliina [53]

The answer is Answer:

y = -1 x + 8

8 0

2 years ago

A tal company has chairs and tables for rent. The total cost to rent 3 chairs and 2 tables is $22. The total cost to rent 5 chai

den301095 [7]

Answer:

$1.5 and $8.75

Step-by-step explanation:

Given data

let tables be x and chairs be y

The total cost to rent 3 chairs and 2 tables is $22

3x+2y=22----------1

The total cost to rent 5 chairs and 6 tables is $60

5x+6y=60---------2

the system of equation is

3x+2y=22----------1X 6

5x+6y=60---------2X 2

18x+12y= 132

- 10x+12y=120

8x+0y= 12

8x= 12

divide both sides by 8

x= 12/8

x=$1.5

put x= 1.5 in 2

5(1.5)+6y=60---------2

7.5+6y=60

6y=60-7.5

6y=52.5

divide both sides by 6

y= 52.5/6

y=$8.75

7 0

2 years ago

Negative decimals on a number line 4

tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

it's B because it says -0.9<u>05</u>

3 0

1 year ago

Read 2 more answers

PLEEASE HELP TIMED!!!!

elixir [45]

Question 1: Option B: $y=\frac{1}{3}x -2$

Question 2: Option D: $y+1=3 (x+1)$

Solution:

Question 1:

The point on the given line are (2, 4) and (4, –2).

Slope of the given line:

$$m=\frac{y_2-y_1}{x_2-x_1}$

$$m=\frac{-2-4}{4-2}$

m = –3.

Slope of perpendicular line = –1 ÷ Slope of the given line

Slope of perpendicular line = $\frac{1}{3}$

Perpendicular line passing through the point (3, 1).

Slope -intercept form using point slope formula,

$y-y_1=m(x-x_1)$

$y-1=\frac{1}{3} (x-3)$

$y-1=\frac{1}{3} x-1$

$y=\frac{1}{3}x -2$

Option B is the correct answer.

Question 2:

The point on the given line are (0, –3) and (2, 3).

Slope of the given line:

$$m=\frac{3+3}{2-0}$

$$m=\frac{6}{2}$

m = 3.

Slope of parallel lines are equal.

Slope of parallel line =3

parallel lines passing through the point (–1, –1).

Point slope formula:

$y-y_1=m(x-x_1)$

$y+1=3 (x+1)$

Option D is the correct answer.

6 0

2 years ago

Read 2 more answers