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Darya [45]
3 years ago
11

An aluminum bar was found to have a mass of 27g. Using water displacement, the volume was measured to be 10 ml. What is the dens

ity of the aluminum? Group of answer choices (27 g)/(10 ml) (10 ml )/(2.70 g) (270 g)/(10 ml) (10 ml )/(27 g)
Chemistry
1 answer:
Pavlova-9 [17]3 years ago
3 0

Answer:

2.7 g/mL:)

An aluminum bar was found to have a mass of 27g. Using water displacement, the volume was measured to be 10 ml. What is the density of the aluminum? Group of answer choices (27 g)/(10 ml) (10 ml )/(2.70 g) (270 g)/(10 ml) (10 ml )/(27 g)

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CuSO4 absorbs light strongly at a wavelength of 635 nm. Consider that you measure the initial intensity of light, Io, entering t
astra-53 [7]

Answer:

The right statement is "The percent transmittance of light, %T, will be higher for Sample 1 compared to Sample 2."

Explanation:

The Beer-Lambert Law states that the absorbance is directly proportional to the concentration of the substance.

Absorbance = εLc

ε: molar absorptivity coeficient

L: optical path length

c: molar concentration

Therefore, if ε and L are the same, the higher the concentration, the higher the absorbance and the lower the transmitance.

Since sample 1 has a higher concentration of CuSO₄ than sample 2, sample 1 has a higher absorbance and lower percent transmittance.

8 0
3 years ago
In a titration of 0.35 M HCl and 0.35 M NaOH, how much NaOH should be added to 45.0 ml of HCl to completely neutralize the acid?
Rom4ik [11]
<span>M(HCl) * </span><span>V(HCl) </span>= <span>M(NaOH) * </span><span>V(<span>NaO<span>H)
</span></span></span>
M(HCl) = 0.35
<span>V(HCl) = 45mL
</span>M(NaOH)= 0.35

now, solne for V(NaOH) by putting these values in the above equation.
M(HCl) * <span>V(HCl) </span>= <span>M(NaOH) * </span><span>V(NaOH)</span>

<span>0.35 * 45 = 0.35 * V(NaOH)</span>

<span>V(NaOH) = 45 mL</span>

8 0
3 years ago
Read 2 more answers
One gram of liquid benzene is burned in a bomb calorimeter. The temperature before ignition was 20.826 ℃, and the temperature af
gtnhenbr [62]

Answer:fH = - 3,255.7 kJ/mol

Explanation:Because the bomb calorimeter is adiabatic (q =0), there'is no heat inside or outside it, so the heat flow from the combustion plus the heat flow of the system (bomb, water, and the contents) must be 0.

Qsystem + Qcombustion = 0

Qsystem = heat capacity*ΔT

10000*(25.000 - 20.826) + Qc = 0

Qcombustion = - 41,740 J = - 41.74 kJ

So, the enthaply of formation of benzene (fH) at 298.15 K (25.000 ºC) is the heat of the combustion, divided by the number of moles of it. The molar mass od benzene is: 6x12 g/mol of C + 6x1 g/mol of H = 78 g/mol, and:

n = mass/molar mass = 1/ 78

n = 0.01282 mol

fH = -41.74/0.01282

fH = - 3,255.7 kJ/mol

4 0
3 years ago
Which statement correctly contrasts science and pseudoscience
mojhsa [17]
brainly.com/question/1470976 Hope this helps!
8 0
3 years ago
N2 + 3 H2 → 2 NH3
sweet [91]

Answer:

B

Explanation:

5 0
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