cesium chloride is another chloride that could be used instead of the calcium chloride dihydrate to produce a solid precipitate with aqueous sodium carbonate
A mineral salt called cesium chloride (CsCl) is occasionally ingested or administered intravenously to cancer patients seeking alternative therapies. However, the FDA has not yet approved any cesium chloride products to treat cancer or other disorders.
In isopycnic centrifugation, cesium chloride is a common medical compound used to separate different forms of DNA. It is a reagent used in analytical chemistry to distinguish ions based on the hue and shape of the precipitate.
Cesium chloride is not proven to be effective in treating cancer. As an alternative to chemotherapy for cancer, cesium chloride is pushed. Supporters assert that cesium prevents tumor cells from proliferating by neutralizing the poisons they release.
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Answer:
The answer is granitic or felsic rocks
Explanation:
Felsic is a term used in geology applied to silicate minerals, magmas and rocks, rich in light elements such as silicon, oxygen, aluminum, sodium and potassium (describs igneous rocks that are relatively rich in elements that form feldspar and quartz). This term is a combination of the words "feldspar" and "silica". Felsic minerals are generally light in color and have a specific gravity of less than 3. The most common felsic minerals are quartz, muscovite, alkaline feldspars (eg orthoclase) and feldspars from the plagioclase series. The most common felsic rock is granite. At the opposite end of the rock spectrum are mafic (rich in iron) and ultramafic (rich in magnesium) rocks and minerals.
<u>Given information:</u>
Mass of H2 = 2 g
Mass of O2 = 32 g
<u>To determine:</u>
Mass of H2O2 produced
<u>Explanation:</u>
The reaction between H2 and O2 can be given as:
H2 + O2 → H2O2
Based on the reaction stoichiometry:
1 mole of H2 reacts with 1 mole of O2 to form 1 mole of H2O2
# moles of H2 = mass of H2 / molar mass of H2 = 2 g/ 2 g.mol-1 = 1 mole
# moles of O2 = mass of O2/ molar mass of O2 = 32 g/ 32 g.mol-1 = 1 mole
Hence for the given reactant conditions, moles of H2O2 produced = 1
Mass of H2O2 = moles of H2O2 * molar mass H2O2 = 1 mole * 34 g.mole-1 = 34 g
<u>Ans</u>: 34 g of H2O2 is produced in this reaction
Answer:
0.5 mole CO2=0. 5×44=22 gm.
68 kg. There are 58 kg salt in 500 gal seawater.
<em>Step 1.</em> Convert gallons to litres
1 US gal = 3.79 L (1 Imp gal = 4.55 L)
<em>Step 2</em>. Find the volume of the seawater
Volume = 500 gal × (3.79 L/1 gal) = 1895 L
<em>Step 3</em>. Find the mass of the seawater
Mass = 1895 L × (1.025 kg/1 L) = 1942 kg
<em>Step 4</em>. Find the mass of the salt
Mass of salt = 1942 kg seawater × (3.5 kg salt/100 kg seawater) = 68 kg salt
