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2 years ago

Here are two column vectors

Mathematics

1 answer:

Contact [7]2 years ago

8 0

Answer:

$a = ( \frac{ - 6}{2} )$

Step-by-step explanation:

-2g=?

$- 2( \frac{3 }{ - 1} ) \\ \\ ( \frac{ - 6}{2} )$

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What's the answer to this

lyudmila [28]

8(14-9)+5
________
2
3. + 6

8(5)+5
______
9 + 6

40 + 5
————
15

45
____
15

= 3

4 0

2 years ago

to get to work truman waited 11 minutes for the bus, then travled 21.78 miles on the bus at a speed of 33 miles per hour how muc

alexgriva [62]

We have 11 as our base value, meaning that we add 11 to something, so we have 11+<something>. To find that something, we want to know how long it takes to go 21.78 miles at 33 miles per hour. To get this, we want to turn miles per hour into minutes per mile and multiply that by 21.78 miles to get our answer. Therefore, we cross them out as shown in the equation to get $\frac{21.78 miles}{1} * \frac{1 hour}{33 miles} * \frac{60 minutes}{1 hour}$

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3 years ago

Given the linear programming problem, use the method of corners to determine where the minimum occurs and give the minimum value

algol [13]

Answer:

Minimum value of function $C=x+10y$ is 63 occurs at point (3,6).

Step-by-step explanation:

To minimize :

$C=x+10y$

Subject to constraints:

$x\leq 3---(1)\\y\leq 9---(2)\\x+y\geq 9----(3)\\x\geq 0\\y\geq 0$

Eq (1) is in blue in figure attached and region satisfying (1) is on left of blue line

Eq (2) is in green in figure attached and region satisfying (2) is below the green line

Considering $x+y\geq 9$ , corresponding coordinates point to draw line are (0,9) and (9,0).

Eq (3) makes line in orange in figure attached and region satisfying (3) is above the orange line

Feasible region is in triangle ABC with common points A(0,9), B(3,9) and C(3,6)

Now calculate the value of function to be minimized at each of these points.

$C=x+10y$

at A(0,9)

$C=0+10(9)\\C=90$

at B(3,9)

$C=3+10(9)\\C=93$

at C(3,6)

$C=3+10(6)\\C=63$

Minimum value of function $C=x+10y$ is 63 occurs at point C (3,6).

3 0

3 years ago

(m^-4/3)^1/4 divided by m^0 n^3/4(m^-3/2 n^2)

postnew [5]

$\frac{(m^{-\frac{4}{3}})^{\frac{1}{4}}}{m^{0}(m^{-\frac{3}{2}}n^{2})} = \frac{m^{-\frac{1}{3}}}{m^{-\frac{3}{2}}n^{2}} = \frac{m^{\frac{3}{2}}}{m^{\frac{1}{3}}n^{2}} = \frac{m^{\frac{7}{6}}}{n^{2}} = \frac{\sqrt[6]{m^{7}}}{n^{2}} = \frac{\sqrt[6]{m^{6} * m}}{n^{2}} = \frac{\sqrt[6]{m^{6}}\sqrt[6]{m}}{n^{2}} = \frac{m\sqrt[6]{m}}{n^{2}}$

6 0

2 years ago

Expand » Kenneth has a total of $25 to spend on books and music CDs. Books are on sale for $5 each, and music CDs are on sale fo

galben [10]

Sense the books on sale for $5 and the CDs are for 10 he brought 1 CD. So he he brought 3 books because do 25-10 and get 15 and books are for $5. Hope that helped.

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3 years ago