Answer:
a
Step-by-step explanation:
its right
Assume a is not divisible by 10. (otherwise the problem is trivial).
<span>Define R(m) to be the remainder of a^m when divided by 10. </span>
<span>R can take on one of 9 possible values, namely, 1,2,...,9. </span>
<span>Now, consider R(1),R(2),......R(10). At least 2 of them must have the sames value (by the Pigeonhole Principle), say R(i) = R(j) ( j>i ) </span>
<span>Then, a^j - a^i is divisible by 10.</span>
<span>5x+10 = y
Subtract 10 from both sides.
5x = y - 10
Divide both sides by 5.
x = 1/5y - 2
Plugin 1/5y - 2 for the y.
5(1/5y - 2)
1 - 10 + 10 = y
1 = y
<span>
</span><span>Your Answer(s)
</span><span>y = 1
</span></span>x = 1/5y - 2
<span>
</span>
Answer:
x = 14
Step-by-step explanation:
You want to solve for x, right?
(x-5)^(1/2)+5=2
You have it right so far.
(x - 5)^(1/2) = -3
(x - 5) = (-3)^2
x - 5 = 9
x = 9 + 5 = 14
