The answer is at least 6.
To solve this, you need to subtract 180 from 400: (400-180=220). After that (I used the fraction/proportion/variable way, but there are others), so 220/400=%(p)/100. Multiply diaganolly, so 400*p=400p, which is equal to 220*100=22000. Therefore, 400p=22000. Now, you have to isolate the variable by dividing both sides by 400: 400p/400=p, and 22000/400=55. Therefore, p=55, or %=55, so the answer is 55%, or C.
The effective current when an AC peak voltage of 18V is applied to a lamp with 4 ohm resistance is 3.18 A.
<h3>What is
current?</h3>
Current is the flow of electrons through a conductor when voltage is applied across the conductor.
Given the peak voltage of 18 V, hence:
The effective current when an AC peak voltage of 18V is applied to a lamp with 4 ohm resistance is 3.18 A.
Find out more on current at: brainly.com/question/24858512
Answer:
1
Step-by-step explanation:
f(x) = x² + 3x
g(x) = 5x + 2
f(3) = 3² + 3 x 3
f(3) = 9 + 9
f(3) = 18
g(3) = 5(3) + 2
g(3) = 15 + 2
g(3) = 17
(f - g)(3) = 18 - 17
(f - g)(3) = 1.
