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vivado [14]
2 years ago
9

Which of the following are solutions to the equation below? Check all that apply. 9x2 – 64 = 0

Mathematics
2 answers:
erik [133]2 years ago
6 0

Answer:

x= 8/3 and x= -8/3

Step-by-step explanation:

Remember the difference of two squares method

a²- b²= (a+b) (a-b)

Given;

9x²-64=0

We notice 9 and 64 are in square form thus can be written as

(3x-8) (3x+8)....................................applying the difference in squares method to simplify

Solving for x

(3x-8) (3x+8) =0

3x-8=0

3x=8

x= 8/3

or

3x+8=0

x= -8/3

Andrej [43]2 years ago
6 0

Answer:

8/3 and -8/3

Step-by-step explanation:

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3) You paid $5 for a bucket of popcorn and $1.25 per candy bar. How many candy bars
Alex73 [517]

4 dollars flat $4.00

Step-by-step explanation:

1.25x4= 5$ 5$+5$=10$

4 0
3 years ago
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I'm solving systems and I don't understand how to do it pls helpp
kaheart [24]

Answer:

Use the process of elimination. I'll only do one example since you have 4.

Step-by-step explanation:

Let's do the first question.

2x-3y=-11

2x+y=9

Our goal here is to be left with one variable to solve, this way we can use the answer for that variable to find the other. A.K.A only find X to plug into the equation to find Y. To do this, we'll use the process of elimination, in which we need to cancel out a variable.

X seems the easiest here. To cancel 2 (in the top equation), you need to have a -2. And that -2 needs to be the x coefficient in the 2nd equation, in order for us to "cancel" it out. To get -2, you multiply 2 by -1.

-1(2x+y)= -1(9)

Note that whatever you do to one side, you need to do it to both sides! Hence, why I also multiplied 9 by -1. You should now be left with:

-2x -y = -9

Now, we cancel out the positive 2 and -2 from both equations by adding the two equations.

2x-3y= 11

+

-2x-y=-9

X cancels out, so we're left with -4y=-20. Solve for Y, which is 5.

-4y=-20

y=5

Now that you have the Y value, plug it into any of the two equations to find your X value.

2x-3y=11

2x-3(5)=11

2x-15=11

2x=26

x=13

And voilah! Our Y value is 5, and our X value is 13.

It's pretty simple once you understand what's going on. All that we did was to cancel out one variable (either X or Y) in the two equations so that we're left with only one variable to solve. If we cancel out X, we only need to solve for Y. You do this by manipulating one of the two equations (doesn't matter which one). Once you find either X or Y, all you need to is to plug it into one of the original equations. Then, you'll have both X and Y.

And that my friend, is the process of elimination. Good luck!

8 0
2 years ago
Read 2 more answers
Question 26: write the equation that describes the line with slope=5 and y-intercept =8 in slope intercept form.example: y=mx+b
elixir [45]

Answer:

y = 5x + 8

Step-by-step explanation:

Start with y = mx + b:  general slope-intercept form, equation of a line:

Replace m with 5, y with 8 and x with 0 (since the y-intercept is (0, 8):

8 = 5(0) + b.  Then b must be 8, and the desired equation is

y = 5x + 8

3 0
2 years ago
X^3-13x^2+40x=0 quadratic
lutik1710 [3]

Answer:

x(x-5)(x-8)

or

x=5

x=8

Step-by-step explanation:

  1. x(x^2-13x+40)
  2. x(x-5) (x-8)
6 0
3 years ago
Use the given values of n and p to find the minimum usual value μ−2σ and the maximum usual value μ+2σ. Round to the nearest hund
lbvjy [14]

Answer:

μ−2σ = 1,089.26

μ+2σ = 1,097.62

Step-by-step explanation:

The standard deviation of a sample of size 'n' and proportion 'p' is:

\sigma=\sqrt{\frac{p*(1-p)}{n} }

If n=1139 and p =0.96, the standard deviation is:

\sigma=\sqrt{\frac{p*(1-p)}{n}}\\\sigma = 0.001836

The minimum and maximum usual values are:

\mu-2\sigma = (p-2\sigma)*n\\\mu+2\sigma = (p+2\sigma)*n

\mu-2\sigma = (0.96-2*0.001836)*1139\\\mu-2\sigma = 1,089.26\\\mu+2\sigma = (0.96+2*0.001836)*1139\\\mu+2\sigma = 1,097.62

5 0
2 years ago
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