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3 years ago

The following formula relates the quantities temperature in Celsius (C) and temperature in kelvins (K).

Mathematics

1 answer:

Oksanka [162]3 years ago

4 0

Answer:

<em>The other two related equations are: $C+273.15= K$ and $K-C= 273.15$ </em>

Step-by-step explanation:

The formula that relates the quantities temperature in Celsius (C) and temperature in kelvins (K) is given by: $C= K-273.15$

First we can add 273.15 to both sides of the equation. So, we will get.....

$C+273.15= K-273.15+273.15\\ \\ C+273.15= K$

Now, we can also subtract K from both sides of the original equation. So, we will get..........

$C-K= K-273.15-K\\ \\ C-K=-273.15\\ \\ K-C= 273.15$

So, the other two related equations are: $C+273.15= K$ and $K-C= 273.15$

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jeka57 [31]

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3 years ago

Read 2 more answers

A landscape architect wished to enclose a rectangular garden on one side by a brick wall costing $20/ft and on the other three s

makvit [3.9K]

Answer:

The dimensions of the garden that minimize the cost is 9.018 feet(length) and 13.528 feet(width)

Step-by-step explanation:

Let the length of garden be x

Let the breadth of garden be y

Area of Rectangular garden = $Length \times Breadth = xy$

We are given that the area of the garden is 122 square feet

So, $xy=122$ ---A

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So, cost of brick along length x = 20 x

On the other three sides by a metal fence costing $10/ft.

So, Other three side s = x+2y

So, cost of brick along the other three sides= 10(x+2y)

So, Total cost = 20x+10(x+2y)=20x+10x+20y=30x+20y

Total cost = 30x+20y

Substitute the value of y from A

Total cost = $30x+20(\frac{122}{x})$

Total cost = $\frac{2440}{x}+30x$

Now take the derivative to minimize the cost

$f(x)=\frac{2440}{x}+30x$

$f'(x)=-\frac{2440}{x^2}+30$

Equate it equal to 0

$0=-\frac{2440}{x^2}+30$

$\frac{2440}{x^2}=30$

$\sqrt{\frac{2440}{30}}=x$

$9.018 =x$

Now check whether it is minimum or not

take second derivative

$f'(x)=-\frac{2440}{x^2}+30$

$f''(x)=-(-2)\frac{2440}{x^3}$

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$f''(x)=-(-2)\frac{2440}{(9.018)^3}$

$f''(x)=6.6540$

Since it is positive ,So the x is minimum

Now find y

Substitute the value of x in A

$(9.018)y=122$

$y=\frac{122}{9.018}$

$y=13.528$

Hence the dimensions of the garden that minimize the cost is 9.018 feet(length) and 13.528 feet(width)

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