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yarga [219]
3 years ago
7

so this boy liked me for years in middle school and i think he finally got over me once i didn't really show much interest in hi

m, but its not that i didn't like him, i was just super shy and not really ready to date, and i didn't think i was good enough for him...like i didn't understand why he liked ME out of any girl in the county. So.. we're in high school now and i kinda still like him but idk what to do to start talking again since it'll be super awkward.. boy and girl opinions accepted... plz help lol
Mathematics
1 answer:
sasho [114]3 years ago
6 0

<em>Ah, female problems, Amiright?</em>

<em>If you don't feel comfortable talking to him, then you don't have to, it's not against the law. And if he tries talking to you and it becomes awkward, make sure that someone is with you that you know will keep a good convo going.</em>

<em>Also</em><em>,</em><em> </em><em>he</em><em> </em><em>probably</em><em> </em><em>liked</em><em> </em><em>you</em><em> </em><em>because</em><em> </em><em>of</em><em> </em><em>your</em><em> </em><em>personality</em><em>,</em><em> </em><em>or</em><em> </em><em>maybe</em><em> </em><em>the</em><em> </em><em>way</em><em> </em><em>you</em><em> </em><em>look</em><em>,</em><em> </em><em>or</em><em> </em><em>talk</em><em>,</em><em> </em><em>or</em><em> </em><em>wear</em><em> </em><em>you</em><em> </em><em>hair</em><em>,</em><em> </em><em>or</em><em> </em><em>even</em><em> </em><em>your</em><em> </em><em>style</em><em>.</em><em> </em><em>The</em><em> </em><em>possiblys</em><em> </em><em>are</em><em> </em><em>endless</em><em>.</em>

<em>Honestly, I've been in </em><em>a</em><em> </em><em>similar</em><em> situation before, that's how I know what to do.</em>

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What is an equation of the line that passes through the point (-6,-8) and is parallel to the line x-2y=6?
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Step-by-step explanation:

Hi there!

<u>What we need to know:</u>

  • Linear equations are typically organized in slope-intercept form: y=mx+b where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)
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<u>1) Determine the slope (m)</u>

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Rearrange this equation into slope-intercept form (this will help us find the slope)

Subtract x from both sides

x-2y-x=6-x\\-2y=-x+6

Divide both sides by -2

y=\frac{1}{2} x-3

Now, we can identify clearly that the slope of the given line is \frac{1}{2} since it's in the place of m. Because parallel lines always have the same slopes, the line we're currently solving for would therefore have a slope of \frac{1}{2} as well. Plug this into y=mx+b:

y=\frac{1}{2}x+b

<u>2) Determine the y-intercept (b)</u>

y=\frac{1}{2}x+b

Plug in the given point (-6,-8)

-8=\frac{1}{2}(-6)+b\\-8=-3+b

Add 3 to both sides to isolate b

-8+3=-3+b+3\\-5=b

Therefore, the y-intercept is -5. Plug this back into y=\frac{1}{2}x+b:

y=\frac{1}{2}x-5

I hope this helps!

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