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The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.
<h3>How to identify similar triangles?</h3>From the image attached, we see that we are given the Parallelogram GRPC. Thus;
A. The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.
B. The proof of the fact that ΔGCB and ΔPEB are similar pairs of triangles is as follow;
∠CGB ≅ ∠PEB (Alternate Interior Angles)
∠BPE ≅ ∠BCG (Alternate Interior Angles)
∠GBC ≅ ∠EBP (Vertical Angles)
C. To find the distance from B to E and from P to E, we will first find PE and then BE by proportion;
225/325 = PE/375
PE = 260 ft
BE/425 = 225/325
BE = 294 ft
Read more about Similar Triangles at; brainly.com/question/14285697
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<u>Answer:</u>
The original selling price is $520.632
<u>Explanation:</u><u> </u>
Consider the initial selling price be $x
After marking down 10%,
Final Selling price = Selling price(1-10%)
Selling price = x – 10% of x = x – 0.1x = 0.9x
After marking 30%
Final Selling price = Selling price(1-10%)
Selling price = 0.9x – 0.3*0.9x = 0.9x – 0.27x = 0.63x
According to the question,
0.63x = 328
Therefore, the original selling price is $520.632