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meriva
3 years ago
12

Write -4i+(1/4-5i)-(-3/4+8i)+17i as a complex number in the standard for

Mathematics
1 answer:
KatRina [158]3 years ago
8 0

Answer:

1+ 0i

Step-by-step explanation:

A complex number is a number which has some real part and some imaginary part.

Standard form of a complex number is represented as

a +bi

Where a is the real part,

and bi is the imaginary part.

And i = \sqrt{-1}

Given complex number:

-4i+\dfrac{1}{4}-5i)-(-\dfrac{3}{4}+8i)+17i\\\Rightarrow -4i+\dfrac{1}{4}-5i + \dfrac{3}{4}-8i+17i\\\Rightarrow  \dfrac{3}{4}+\dfrac{1}{4}-4i -5i-8i+17i\\\Rightarrow  \dfrac{3+1}{4}-17i+17i\\\Rightarrow \dfrac{4}{4}+0i\\\Rightarrow 1 + 0i

Hence, the standard form is 1+ 0i.

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