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Stells [14]
3 years ago
14

What is the range of f(x) = -x2 + 4, if the domain is {2,0,1}?

Mathematics
1 answer:
Viktor [21]3 years ago
5 0

Answer:

k12

Tell me the answer

Step-by-step explanation:

You might be interested in
The weights of adobe bricks used for construction are normally distributed with a mean of 3 pounds and a standard deviation of 0
dedylja [7]

Answer:  a) 0.8413, b) 0.9987.

Step-by-step explanation:

Since we have given that

Mean = 3 pounds

Standard deviation = 0.25 pounds

n = 28 bricks

So, (a) What is the probability that all the bricks in the sample exceed 2.75 pounds?

P(X>2.75)\\\\=P(z>\dfrac{2.75-3}{0.25}\\\\=P(z>\dfrac{-0.25}{0.25})\\\\=P(z>-1)\\\\=0.8413

b) What is the probability that the heaviest brick in the sample exceeds 3.75 pounds?

P(X>3.75)\\\\=P(z>\dfrac{3.75-3}{0.25})\\\\=P(z>\dfrac{0.75}{0.25})\\\\=P(z>3)\\\\=0.9987

Hence, a) 0.8413, b) 0.9987.

4 0
3 years ago
Write an equation for each line that contains the given pair of points. (-6,1) (2,3)
Travka [436]

Answer:

y = .25x + 2.5

Step-by-step explanation:

First find the slope which is m in y = mx + b. y = mx + b is the standard form for a line.

m = (y₂-y₁)/(x₂-x₁)

m = (3-1)/(2+6)

m = 2/8

m = 1/4

Plug that in.

y = 1/4x + b

To find b plug in one of the two points and solve.

3 = 1/4(2) + b

3 = 1/2 + b

3 - 1/2 = 1/2 - 1/2 + b

2.5 = b

4 0
4 years ago
The sales tax rate for the state of Washington was 9.4%. what is the state sales tax on a $3900 car in Washington? What is the f
MAXImum [283]

Answer:

3900 x.094 = 366.60

366.6+3900=4266.60

5 0
3 years ago
A small junior college had an enrollment of 7,843 students in the year 1990 and 8,793 students in the year 2000. Let x=0 represe
abruzzese [7]

Correct answer is: (0,7843) and (10,8793)

Solution:-

Given that a junior college has an enrollment of 7843 students in 1990 and 8793 students in year 2000.

We have to write this data as (x,y) .

Where x= years after 1990 and y=number of students enrolled.

Since in 1990, 7843 students enrolled, x = 1990-1990=0

And y=7843.

Hence one ordered pair is (0,7843).

Let us find the years after 1990 for 2000 = 2000-1990 =10

Hence another ordered pair is (10,8793).

4 0
4 years ago
Simplify 12x6 y7 18 x3y5.
Ksivusya [100]

Answer:

216x^9y^12

Step-by-step explanation:

5 0
3 years ago
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