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3 years ago

How to find the perimeter of shapes

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

5 0

You add the legnths of the sides together exg
if you have rectangle with width=2 legnth=3
permiter=w+w+l+l=2+2+3+3=10

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Can someone help me? Files attached! What answer choices go to what figure? :D

den301095 [7]

Since the center is considered the corner that they both share, here are the answers figure a goes with the first, figure b goes with the last, figure c goes with the second, and figure d goes with the third. Hope this helps.

3 0

3 years ago

Which box plot correctly displays the data set with a maximum of 48, a minimum of 27, a median of 36, an upper quartile of 45, a

Vitek1552 [10]

Answer:

Image 1

Step-by-step explanation:

To answer this question, we need to know how to use a box plot.

I've attached an image that demonstrates this well and can teach you what each part of the box plot means.

Specifically, the 2 farthest dots at the end are the minimum and maximum. The two sides where the box starts are the lower and upper quartiles. Finally, the line in the middle of the box is the median.

With this, we can analyze each box plot and determine which one is correct.

Box Plot 1: Everything is plotted correctly- Maximum and minimum plotted correctly, median plotted correctly, upper and lower quartile plotted correctly.

Box Plot 2: Everything plotted correctly EXCEPT maximum of 48 is represented at 46.

Box Plot 3: Everything plotted correctly EXCEPT the upper quartile of 45 is at 39.

Box Plot 4: Upper quartile represented at 39 and maximum represented at 46 are both incorrect.

4 0

2 years ago

PLEASE HELP ME I BEG I WILL GIVE BRAINLIEST

ohaa [14]

Answer:

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

Step-by-step explanation:

7 0

2 years ago

The graph below shows the cost of pens based on the number of pens in a pack. What would be the cost of one pen?

MaRussiya [10]

The answer would be B. $1.75

5 0

3 years ago

Read 2 more answers

A 15 ft. telephone pole has a wire that extends from the top of the pole to the ground. The wire and the ground form a 42° angle

Lorico [155]

Answer:

Correct choice is A

Step-by-step explanation:

Consider right triangle ABC formed by the telephone pole (side AB) and ground (side BC). In this triangle AC is the length of the wire, BC is the distance from the base of the pole to the spot where the wire touches the ground and AB=15 ft, ∠ACB=42°.

Then

$\sin 42^{\circ}=\dfrac{AB}{AC}\Rightarrow AC=\dfrac{AB}{\sin 42^{\circ}}=\dfrac{15}{\sin 42^{\circ}}\approx 22.4\ ft.$
$\tan 42^{\circ}=\dfrac{AB}{BC}\Rightarrow BC=\dfrac{AB}{\tan 42^{\circ}}=\dfrac{15}{\sin 42^{\circ}}\approx 16.7\ ft.$

8 0

3 years ago