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exis [7]
3 years ago
8

What's the mode and median for 22,36,9,27,30,20

Mathematics
1 answer:
zalisa [80]3 years ago
6 0
Mode: none. All values occur once
Median 24.5
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Find the midpoint of the line segment with the given endpoints: (-1, -6) and (-6, 5).
Vikentia [17]

Answer:

Step-by-step explanation:

First, we will find the midpoint for the x - coordinate first.

Midpoint (x) = \frac{-1+(-6)}{2} \\=\frac{-1-6}{2} \\=\frac{-7}{2} \\=-3.5

Now we will find the midpoint for the y - coordinate.

Midpoint (y) = \frac{-6+5}{2} \\=\frac{-1}{2} \\=-0.5

Therefore from these 2 values we know that the midpoint of this 2 points is (-3.5,-0.5)

8 0
2 years ago
Labrador Retriever weighs 48 kg after a diet and exercise program the dog weighs 43 kilograms to determine if this shows a perce
ExtremeBDS [4]

Answer:

percentage change in weight ≈ 10%

Step-by-step explanation:

The dog weighed 48 kg after a diet and after an exercise program the dog had a weight of 43 kg. This means the dog loss weight since the dog weight decreased from an initial value of 48 kg to 43 kg. The decrease in weight can be calculate as

decrease in weight = original weight - new weight

original weight  = 48 kg

new weight = 43 kg

decrease in weight = 48 - 43 = 5 kg

Since the weight decrease their will be a percentage decrease in weight.

% decrease = decrease in weight/original weight × 100

% decrease = 5/48 × 100

% decrease = 500/48

% decrease = 10. 42666666667

percentage change in weight ≈ 10%

5 0
3 years ago
Find the indefinite integral. (Use C for the constant of integration.)
mart [117]

Answer:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

tep-by-step explanation:

In order to find the integral:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx

we can do the following substitution:

Let's call

u=(x^3-x^2+x)

Then

du = (3x^2-2x+1) dx

which allows us to do convert the original integral into a much simpler one of easy solution:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx  = \int\ {u^7 \, du = \frac{1}{8} \,u^8 +C

Therefore, our integral written in terms of "x" would be:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

7 0
3 years ago
a rectangular garden is 47 ft longer than it is wide. its perimeter is 314 ft. what is the equation to describe the width and le
Ronch [10]
The perimeter = 2 length + 2 width 

the length = the width +47

314 = 2*(w+47) +2w

314 = 2w +94 +2w

220 =4w

w= 220/4 = 55

l = 55+47 = 102

the length = 102 ft

the width = 55 ft 

hope helped 

3 0
4 years ago
A rectangle has height of 3,27 meters and a base measuring 1.29 meters as shown which of the following is closest to x the lengt
luda_lava [24]

Answer:

from pythogarus theorem:

x =  \sqrt{ {3.27}^{2} +  {1.29}^{2}  }  \\ x =  \sqrt{12.357}  \\ x = 3.52 \: meters

4 0
3 years ago
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