What are the first 5 terms of the sequence generated by the formula an= 2(n!)
1 answer:
Answer:
2, 4, 12, 48, 240
Step-by-step explanation:
We have the recursive formula a_n = 2*(n!)
Find:
a_1 = 2* 1! = 2
a_2 = 2*(2!) = 4
a_3 = 2*(3!) = 2*6 = 12
a_4 = 2*(4!) = 2*24 = 48
a_5 = 2*(5!) = 2*5*24 = 240
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