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Ray Of Light [21]
2 years ago
5

Is 5x - 2 a non linear function

Mathematics
2 answers:
Oksana_A [137]2 years ago
4 0
Yes, 5x-2 is a non linear function
Semmy [17]2 years ago
3 0

Answer:

yes

Step-by-step explanation:

You might be interested in
How to solve this pythagoras theorem
My name is Ann [436]

Answer:

see explanation

Step-by-step explanation:

The hypotenuse is the longest side thus is (4x + 1)

The legs are 2x and (4x - 1)

Using Pythagoras' theorem, then

(4x + 1)² = (2x)² + (4x - 1)² ← expanding factors

16x² + 8x + 1 = 4x²  + 16x² - 8x + 1 , that is

16x² + 8x + 1 = 20x² - 8x + 1 ( subtract 20x² - 8x + 1 from both sides )

- 4x² + 16x = 0 ( multiply through by - 1 )

4x² - 16x = 0 ← factor out 4x from each term

4x(x - 4) = 0

Equate each factor to zero and solve for x

4x = 0 ⇒ x = 0

x - 4 = 0 ⇒ x = 4

Now x > 0, thus x = 4

2x = 2(4) = 8

4x - 1 = 4(4) - 1 = 16 - 1 = 15

4x + 1 = 4(4) + 1 = 16 + 1 = 17

Thus

perimeter = 8 + 15 + 17 = 40 cm

3 0
3 years ago
On a coordinate plane, parallelogram A B C D has points (3, 6), (6, 5), (5, 1), and (2, 2).
Vlad1618 [11]

Answer:

Area of parallelogram ABCD=13.05=13 Sq.Units

Step-by-step explanation:

Given;

A(3,6)  B(6,5)  C(5,1) and D(2,2)

are points for parallelogram

To Find:

Area of Parallelogram ABCD

Solution:

By using distance formula  we can calculate for each length of parallelogram

But by property of parallelogram

Opposite side are parallel and equal in length

So AB|| DC i.e AB=DC

And AC|| BD i.e BD=AC

Hence  I.e Dist(AB)=Dist(DC)

Now construct the ABCD parallelogram ,on graph so as to find angle made by parallelogram with plane .

(Refer the attachment)

Now

Distance of AD=Sqrt[(2-3)^2+(2-6)^2]

=Sqrt[1+16]

=4.123

Similarly for AB=Sqrt[(6-3)^2+(5-6)^2]

=Sqrt[9+1]

=3.16

ABOVE VALUES ARE SAME AS GRAPH (REFER THE ATTACHMENT)

Now ,angle made by parallelogram with plane and it is 90 degree i.e the

Now Area of parallelogram(ABCD)=a*b*sinФ

here a=4.123 units and b=3.16 units and  Ф=90

Area of parallelogram=3.167*4.123*sin90

=3.167*4.123

=13.05 sq. units

3 0
2 years ago
Read 2 more answers
Hi who can help me do this 2quetion,I will mark brainlest ​
hodyreva [135]

Step-by-step explanation:

8.  log_{10}(2.15)   = 0.332 \: then \:   log_{10}(21500)   = ..... \\  log(21500)  =  log(2.15 \times 10000)  \\   =  log(2.15)  +  log(10000)  \\   = log_{10}(2.15)  +  log_{10}( {10}^{4} )  \\  = 0.332 + 4 log_{10}(10)  \\  = 0.332 + 4(1) \\  log_{10}(21500)  = 4.332

9. log(2)=a, log(3)=b, then log(36)=______

log(36) = log(6*6) = log(6) + log(6)

log(36)= log(6) + log(6)

log(36) = log(3*2) + log(3*2)

log(36) = (log(3) + log(2)) + (log(3) + log(2))

log(36) = (a + b) + (b + a)

log(36) = a + b + b + a

log(36) = 2a + 2b

5 0
2 years ago
Read 2 more answers
In​ Marissa's calculus​ course, attendance counts for 15​% of the​ grade, quizzes count for 20​% of the​ grade, exams count for
Alexandra [31]

Answer:

Her average was 87.35% on this course.

Step-by-step explanation:

In order to determine Marissa's average we need to take the average she has on each of the cattegories and find how much that relates to the weight of the  cattegory on the final grade. We have:

Attendance counts for 15% of the grade and she has 100% average on that. So we have:

attendance = weight*(Marissa's average)

attendance = 15%*(100/100) = 15%

Quizzes counts for 20% of the grade and she has a 93% average on that. So we have:

Quizzes = weigth*(Marissa's average)

Quizzes = 20%*(93/100) = 18.6 %

Exams counts for 50% of the grade and she has a 82% average on that. So we have:

Exams = weigth*(Marissa's average)

Exams = 50%*(82/100) = 41%

The final exam counts for 15% of the grade and she has a average of 85% on that so we have:

Finals = 15%*(85/100) = 12.75%

So her grade is the sum of all the cattegories:

Course's average = 15+18.6+41+12.75 = 87.35 %

4 0
3 years ago
Read 2 more answers
____________________
luda_lava [24]

Angle BOC = 120

PROOF

Angle A + Angle B + Angle C = 180

So, Angle B + Angle C = 120 (Angle A = 60)

Now 1/2 (Angle B + Angle C) = 60

1/2 Angle B + 1/2 Angle C = 60..............i

In triangle BOC

1/2 Angle B + 1/2 Angle C + Angle BOC =180

(BO and CO are angle bisectors)

Or 60 + Angle BOC = 180 (using i)

OR ANGLE BOC = 120

6 0
3 years ago
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