Answer:
Step-by-step explanation:
y = sin(t^2)
y' = 2tcos(t^2)
y'' = 2cos(t^2) - 4t^2sin(t^2)
so the equation become
2cos(t^2) - 4t^2sin(t^2) + p(t)(2tcos(t^2)) + q(t)sin(t^2) = 0
when t=0, above eqution is 2. That is, there does not exist the solution. so y can not be a solution on I containing t=0.
Answer:
A) -72xy
Step-by-step explanation:
Hope this helps
Please give me Brainliest
I think you could try adding up all the x and then divided
The answer would be D I and II only
My work:
The only answer that has both statement I and statement II as true is D<span>, but if you have time and want to be absolutely thorough, you can also check to see if statement III is true </span>
Answer:
5n - 7 < 23
Step-by-step explanation:
