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choli [55]
3 years ago
7

1. The triangle depicted by the drawing has an actual area of 36 square units. What is the scale of the drawing? (Note: Each squ

are on the grid has a length of 1 unit.) What's the answer to this??

Mathematics
1 answer:
Jet001 [13]3 years ago
5 0

Answer:

the the scale of the drawing is 1/4

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  Please have a look at the attached photo.

As we know that, the formula to find the are of a triangle is:

A = 1/2 b*h where:

  • b is the base
  • h is the height

From the photo, we can see that, the height is 3 units and the base is 6 units. So the area of the shaded triangle is:

A = 1/2 6*3 = 9 square units

Given that the triangle depicted by the drawing has an actual area of 36 square units. So the the scale of the drawing is:

area of the shaded triangle / the actual area

9 /36 = 1/4

Hope it will find you well.

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Elaine has three types of nuts, peanuts, cashews and almonds, that she combines and stores in a large container: There are three
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200 σ j=1 2j( j 3) describe the steps to evaluate the summation. what is the sum?
ziro4ka [17]

The sum of the equation is  = 5494000.

<h3>What does summation mean in math?</h3>

The outcome of adding numbers or quantities mathematically is a summation, often known as a sum. A summation always has an even number of terms in it. There may be just two terms, or there may be 100, 1000, or even a million. Some summations include an infinite number of terms.

<h3>Briefing:</h3>

Distribute 2j to (j+3).

Rewrite the summation as the sum of two individual summations.

Evaluate each summation using properties or formulas from the lesson.

The lower index is 1, so any properties can be used.

The sum is 5,494,000.

<h3>Calculation according to the statement:</h3>

\sum_{j=1}^{200} 2 j(j+3)

simplifying them we get:

\sum_{j=1}^{200} 2 j^{2}+6 j

Split the summation into smaller summations that fit the summation rules.

\sum_{j=1}^{200} 2 j^{2}+6 j=2 \sum_{j=1}^{200} j^{2}+6 \sum_{j=1}^{200} j

\text { Evaluate } 2 \sum_{j=1}^{200} j^{2}

The formula for the summation of a polynomial with degree 2

is:

\sum_{k=1}^{n} k^{2}=\frac{n(n+1)(2 n+1)}{6}

Substitute the values into the formula and make sure to multiply by the front term.

(2)$$\left(\frac{200(200+1)(2 \cdot 200+1)}{6}\right)$$

we get: 5373400

Evaluating same as above : 6 \sum_{j=1}^{200} j

we get: 120600

Add the results of the summations.

5373400 + 120600

= 5494000

The sum of the equation is  = 5494000.

To know more about  summations visit:

brainly.com/question/16679150

#SPJ4

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