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2 years ago

A Zoo keeps a tiger-to-lion ratio of 7:3. If the Zoo has room for 70 animals,

Mathematics

2 answers:

Y_Kistochka [10]2 years ago

6 0

Answer:

Step-by-step explanation:

7x7=49

3x7=21

49+21=70

tekilochka [14]2 years ago

6 0

Answer:

49 tigers

Step-by-step explanation:

Let, there are 7x numbers of tigers

and 3x numbers of lions, where x is a proportionate constant.

Then by the condition,

7x+3x= 70

or, 10x =70

or, x = 7

so, tigers = 7×7= 49

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PLEASE HELP ASAP ASAP URGENT WILL GIVE BRAINLIEST

Luden [163]

Answer:

for the solve and check:

$2\frac{3}{8}+x=3\frac{1}{4} \\2\frac{3}{8}-2\frac{3}{8}+x=3\frac{1}{4}-2\frac{3}{8}\\\\x=3\frac{1}{4}-2\frac{3}{8}\\\\\\x=\frac{7}{8}$

----------------------------------------------------

$3\frac{3}{8}+x=4\frac{1}{4} \\3\frac{3}{8}-3\frac{3}{8}+x=4\frac{1}{4}-3\frac{3}{8}\\\\x=4\frac{1}{4}-3\frac{3}{8}\\\\\\x=\frac{7}{8}$

for the second solve and check:

$4\frac{3}{8}+x=5\frac{1}{4} \\4\frac{3}{8}-4\frac{3}{8}+x=5\frac{1}{4}-4\frac{3}{8}\\\\x=5\frac{1}{4}-4\frac{3}{8}\\\\\\x=\frac{7}{8}$

----------------------------------------------------

$5\frac{3}{8}+x=6\frac{1}{4} \\5\frac{3}{8}-5\frac{3}{8}+x=6\frac{1}{4}-5\frac{3}{8}\\\\x=6\frac{1}{4}-5\frac{3}{8}\\\\\\x=\frac{7}{8}$

8 0

2 years ago

Read 2 more answers

5(2x - 3) + 2 (3x + 1)

astraxan [27]

1/3(2x - 3) + 1 = 1/4(3x + 5) - 2
2x/3 - 3/3 + 1 = 3x/4 + 5/4 - 2
2x/3 - 1 + 1 = 3x/4 + 5/4 - 2
2x/3 - 3x/4 - 0 = 3x/4 - 3x/4 + 5/4 - 2
2x*4/3*4 - 3x*3/4*3 = 0 + 5*1/4*1 - 2*4/1*4
8x/12 - 9x/12 = 5/4 - 8/4
(8x - 9x)/12 = (5 - 8)/4
-x/12 = -3/4
-x/12 * 12 = -3/4 * 12
-x = -36/4
-x * -1 = -36/4 * -1
x = 36/4
x = 9
Done

For check the answer
let x = 9
1/3(2[9] - 3) + 1 = 1/4(3[9] + 5) - 2
1/3(18 - 3) + 1 = 1/4(27 + 5) - 2
1/3(15) + 1 = 1/4(32) - 2
15/3 + 1 = 32/4 - 2
15/3 + 3/3 = 32/4 - 8/4
18/3 = 24/4
6 = 6
therefor
x = 9 is a correct answer

6 0

3 years ago

Pipe leaks 1.5 gallons a day how much in a week

qwelly [4]

Well, that would be 1.5x7.. which is 10.5 :) your welcome

5 0

3 years ago

Read 2 more answers

Maximize the objective function P = 2x + 1.5y for the feasible region shown. State the maximum value for P and the ordered pair

umka2103 [35]

Incomplete question. However, let's assume this are feasible regions to consider:

Points:

- (0, 100)

- (0, 125)

- (0, 325)

- (1, 200)

Answer:

Maximum value occurs at 325 at the point (0, 325)

Step-by-step explanation:

Remember, we substitute the points value for x, y in the objective function P = 2x + 1.5y.

- For point (0, 100): P= 2(0) + 1.5 (100) =150

- For point (0, 125): P= 2(0) + 1.5 (125) =187.5

For point (0, 325): P= 2(0) + 1.5 (325) = 487.5

For point (1, 200): P= 2(1) + 1.5 (200) = 302

Therefore, we could notice from the above solutions that at point (0,325) we attain the maximum value of P.

7 0

2 years ago

Un rectangulo de madera se uso para en marcar un espejo en forma de rombo.Si los lados del marco miden 80.5 cm y 36.4, y las dia

QveST [7]

Answer:

1465.1 cm²

Step-by-step explanation:

El espejo en forma de diamante tiene la forma de rombo

Tenga en cuenta que: las diagonales del rombo tienen las mismas medidas de esos lados

Por lo tanto, el área del espejo se calcula como:

1/2 × Diagonal 1 × Diagonal 2

Diagonal 1 = 80.5 cm

Diagonal 2 = 36.4 cm

= 1/2 × 80.5 cm × 36.4 cm

= 2930.2 cm² / 2

= 1465.1 cm²

Por tanto, el área del espejo es 1465.1 cm².

8 0

2 years ago