You would use the cosine rule for this as you have 2 lines and are given the angle between them
The angle can be figured out easily as the clock has 12 equal components, meaning each component is 360/12 which is 30
As there are 5 components between A and B the angle is 30*5 =150
You can plug all of this into the cosine rule
a^2= b^2+c^2-2bcCos(A)
So a = sqrt( 10^2 +7^2 -(2*10*7) cos150)
a=16.4 to 3 sf
2/a= a/50
Cross multiply:
a* a= 2*50
⇒ a^2= 100
⇒ a= √100 or a= -√100
⇒ a= 10 or a= -10
Final answer: a= 10 or a= -10~
Answer:
Step-by-step explanation:
From the given information; Let's assume that R should represent the set of all possible outcomes generated from a bit string of length 10 .
So; as each place is fitted with either 0 or 1

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0
Now;
if a 0 bit and a 1 bit are equally likely
The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:
; 

You shoulda just paid attention to class my guy, nobody can answer this.