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satela [25.4K]
3 years ago
7

A clothing company plans to shear at least 700700700 sheep today. All novices shear the same number of sheep per day, and all ex

perts shear the same number of sheep per day.
Let NNN represent the number of novices and EEE represent the number of experts needed for the company to meet its goal.
7N+12E \geq 7007N+12E≥7007, N, plus, 12, E, is greater than or equal to, 700
According to the inequality, how many sheep does each novice or expert shear per day?
Each novice shears
sheep, and each expert shears
sheep.
Can the company achieve its goal by employing 606060 novices and 151515 experts?
Mathematics
1 answer:
rusak2 [61]3 years ago
6 0
Its A because if u add it all up then divides thats your answer
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Write the integral and solve for the area under the curve:
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Answer:

Integral: \int\limits^\pi _0 {3sinx} \, dx

Area: 6

Step-by-step explanation:

\int\limits^\pi _0 {3sinx} \, dx  = -3[cosx]_{0} ^{\pi} = 6

4 0
2 years ago
there are 5 more than twice as many students taking Algebra 1 then taking algebra 2. If there are 44 students taking Algebra 2,
Temka [501]

Answer:

93

Step-by-step explanation:

Key :

A1 = Algebra 1

A2 = Algebra 2

Alright so basically lets first look at the info they gave us :

We have 5 more than twice as many students taking A1 than we do A2.

We have 44 students taking A2.

And we need to find the least amount of students that could be taking A1.

So we need to take the amount of students taking A2 (44) and double it to find the amount taking A1.

So we can do 44 x 2 = 88 to get this.

But the problem also states there is 5 more then twice the number of students taking A2.

So we have that 88 but now we just need to add 5 to make up for them telling us that in the problem.

So :

88 + 5 = 93

Our final answer and least amount of students taking A1 is 93 students.

8 0
3 years ago
Read 2 more answers
Tom has just received a new job offer. He is told that his starting salary will be 75,000.00 per year. He is also told that his
Lesechka [4]
Hat is the slope intercept equation
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The driving distance between Manchester and London is 195 miles. Faris intends to travel from Manchester to London by coach. The
s2008m [1.1K]

Question:

The driving distance between Manchester and London is 195 miles. Faris intends to travel from Manchester to London by coach. The coach will leave Manchester at 3:30 pm. Faris assumes that the coach will travel at an average speed of 50 mph; using his assumption workout Faris’s arrival time in London

Answer:

Arrival = 7:24pm

Step-by-step explanation:

Given

Distance = 195\ miles

Speed = 50mi/hr

Take\ off = 3:30\ pm

Required

Determine the time of arrival

First, we need to calculate the time to complete the journey.

Speed = \frac{Distance}{Time}

Make Time the subject

Time= \frac{Distance}{Speed }

Substitute values for Distance and Speed

Time= \frac{195mi}{50mi/hr}

Time= 3.9hr

The arrival time is:

Arrival = Take\ off + Time\ Taken

Arrival = 3:30pm + 3.9\ hours

Split

Arrival = 3:30pm + 3\ hours + 0.9\ hours

Arrival = 6:30pm + 0.9\ hours

Convert 0.9 hours to minutes

Arrival = 6:30pm + 0.9 * 60\ mins

Arrival = 6:30pm + 54\ mins

Arrival = 7:24pm

7 0
3 years ago
Two trains leave stations
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Total distance 272 miles.
Total speed (when travelling toward each other) = 75+95=170 mph
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