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rosijanka [135]
3 years ago
6

What is the set fee, or initial value, of this function

Mathematics
1 answer:
Ber [7]3 years ago
6 0
Answer:
The set fee would be $15

Explanation:
The set fee is the starting value. This means that it is the value of the y at x = 0 (y-intercept).

To get the set fee, we would first need to get the equation of the line.

Equation of the linear line has the following general formula:
y = mx + c
where m is the slope and c is the y-intercept

1- getting the slope:
we are given two points which are:
(20,25) and (50,40)
the slope = \frac{y2-y1}{x2-x1}=  \frac{40-25}{50-20} = 0.5

The equation now is:
y = 0.5x + c

2- getting the value of the y-intercept:
To get the value of the c, we will use any of the given points, substitute in the equation and solve for c.
I will choose the point (20,25)
y = 0.5x + c
25 = 0.5(20) + c
25 = 10 + c
c = 15

The equation of the line representing the scenario is:
y = 0.5x + 15

Now, we know that the value of the c is the y-intercept which is the initial value of the function at x=0.
In our situation, this represents the set fee.

Hope this helps :)
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Answer:

15.2\ units

Step-by-step explanation:

step 1

Plot the vertices of the polygon to better understand the problem

we have

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using a graphing tool

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see the attached figure

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d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 2

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d=\sqrt{(3-1)^{2}+(-3+2)^{2}}

d=\sqrt{(2)^{2}+(-1)^{2}}

d_A_B=\sqrt{5}=2.24\ units

step 3

<em>Find the distance BC</em>

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substitute in the formula

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d=\sqrt{(2)^{2}+(2)^{2}}

d_B_C=\sqrt{8}=2.83\ units

step 4

<em>Find the distance CD</em>

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substitute in the formula

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d=\sqrt{(-1)^{2}+(3)^{2}}

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step 5

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The complete question is

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