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4 years ago

Simplify (4/5) (5/6) (6/7) (7/8) (8/9)

Mathematics

2 answers:

egoroff_w [7]4 years ago

8 0

4/9 thank you for the points

JulijaS [17]4 years ago

5 0

Answer:

4/9

Step-by-step explanation:

using cross canceling you see

(4(5)(6)(7)(8))/(5(6)(7)(8)(9))

everything cancels except for the 4 on top and the 9 on the bottom so

4/9

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52.48 which digit in the tens place

goldfiish [28.3K]

The tenth place would be. . 4

The TENS place would be 5

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3 years ago

Verify the identity. cotangent x equals StartFraction 1 plus cosine 2 x Over sine 2 x EndFractioncot x= 1+cos2x sin2x Use the ap

lutik1710 [3]

Answer with Step-by-step explanation:

We are given that

RHS

$\frac{1+Cos2x}{Sin2x}$

We have to verify the identity.

We know that

$1+Cos2x=2Cos^2 x$

$Sin2x=2SinxCos x$

Using the formula

$\frac{2Cos^2x}{2SinxCosx}$

$\frac{Cosx}{Sinx}$

$Cot x$

By using the formula

$Cotx=\frac{Cosx}{Sinx}$

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Hence, verified

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3 years ago

Can someone find x and y plz

riadik2000 [5.3K]

Answer:

x=0, y=-3

Step-by-step explanation:

Input x=y+3 into 6x-5y=15 to get:

6(y+3)-5y=15

Solve for y

6y+18-5y=15

y+18=15

y=-3

Plug in y to get x

3 0

3 years ago

4 + 4 (1 + 5m) = -132

MrRissso [65]

Answer:

m=-7

Step-by-step explanation:

4+4+20m=-132

8+20m=-132

20m=-132-8

20m=-140

m=-7

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3 years ago

Will Mark Brainiest!!! Simplify the following:

xz_007 [3.2K]

Answer:

1.B

2.A

3. B

Step-by-step explanation:

1. $\frac{x+5}{x^{2} + 6x +5 }$

We have the denominator of the fraction as following:

$x^{2} + 6x + 5 \\= x^{2} + (1 + 5)x + 5\\= x*x + 1x + 5x + 5*1\\= x ( x + 1) + 5(x + 1)\\= (x + 1) (x + 5)$

As the initial one is a fraction, so that its denominator has to be different from 0.

=> ( $x^{2} +6x+5$ ) ≠ 0

⇔ (x +1) (x +5) ≠ 0

⇔ (x + 1) ≠ 0; (x +5) ≠ 0

⇔ x ≠ -1; x ≠ -5

Replace it into the initial equation, we have:

$\frac{x+5}{x^{2} + 6x +5 } = \frac{x+5}{(x+1)(x+5)}$

As (x+5) ≠ 0; we divide both numerator and denominator of the fraction by (x +5)

=> $\frac{x+5}{x^{2} + 6x +5 } = \frac{x+5}{(x+1)(x+5)} = \frac{1}{x+1}$

So that $\frac{x+5}{x^{2} + 6x +5 } = \frac{1}{x+1}$ with x ≠ 1; x ≠ -5

So that the answer is B.

2. $\frac{(\frac{x^{2} -16 }{x-1} )}{x+4}$

As the initial one is a fraction, so that its denominator has to be different from 0

=> x + 4 ≠ 0

=> x ≠ -4

As $\frac{x^{2}-16 }{x-1}$ is also a fraction, so that its denominator (x-1) has to be different from 0

=> x - 1 ≠ 0

=> x ≠ 1

We have an equation: $x^{2} - y^{2} = (x - y ) (x+y)$

=> $x^{2} - 16 = x^{2} - 4^{2} = (x -4) (x +4)$

Replace it into the initial equation, we have:

$\frac{(\frac{x^{2} -16 }{x-1} )}{x+4} \\= \frac{x^{2} -16 }{x-1} . \frac{1}{x + 4}\\= \frac{(x-4)(x+4)}{x-1}. \frac{1}{x + 4}$

As (x + 4) ≠ 0 (proven above), we can divide both numerator and the denominator of the fraction by (x +4)

=> $\frac{(x-4)(x+4)}{x-1} .\frac{1}{x+4} =\frac{x-4}{x-1}$

So that the initial equation is equal to $\frac{x-4}{x-1}$ with x ≠-4; x ≠1

=> So that the correct answer is A

3. $\frac{x}{4x + x^{2} }$

As the initial one is a fraction, so that its denominator (4x + x^2) has to be different from 0

We have:

(4x + x^2) = 4x + x.x = x ( x + 4)

So that: (4x + x^2) ≠ 0 ⇔ x ( x + 4 ) ≠ 0

⇔ $\left \{ {{x\neq 0} \atop {(x+4)\neq0 }} \right.$ ⇔ $\left \{ {{x\neq 0} \atop {x \neq -4 }} \right.$

As (4x + x^2) = x ( x + 4) , we replace this into the initial fraction and have:

$\frac{x}{4x + x^{2} } = \frac{x}{x(x+4)}$

As x ≠ 0, we can divide both numerator and denominator of the fraction by x and have:

$\frac{x}{x(x+4)} =\frac{x/x}{x(x+4)/x} = \frac{1}{x+4}$

So that $\frac{x}{4x+x^{2} } = \frac{1}{x+4}$ with x ≠ 0; x ≠ -4

=> The correct answer is B

3 0

4 years ago