6P3 => 6!/(6-3)! = 120.
I can't very well explain, but I hope it works.
Answer:
m∠P =119
m∠Q = 61
Step-by-step explanation:
m∠P = 2(∠Q)-3 or p=2(q)-3
supplementary angles so they combine to equal 180!
soooooo we can take
q+p=180
input what p equals and you get
q+ 2(q)-3=180
3q-3=180
3q=183
q=61
now we have what m∠Q is, so just subtract that from 180 to get m∠P
180-61=119
Answer:
Step-by-step explanation:
yes, (given number) / 5
Answer:
K'= (-1,-1)
J'= (-1,-5)
L'= (0,-3)
Step-by-step explanation:
What you do here is, input the (x,y) coordinates into the translation.
For example, the original point K is (-3,5). Insert this into the translation.
(-3,5) → (-3+2, 5-8) = (-1,-3)
Repeat this for the next coordinates of L and J.
J= (-3,3)
(-3,3) → (-3+2, 3-8) = (-1,-5)
L= (-2, 5)
(-2, 5) → (-2+2, 5-8) = (0,-3)
Answer: a) 4.6798, and b) 19.8%.
Step-by-step explanation:
Since we have given that
P(n) = 
As we know the poisson process, we get that
So, for exactly one car would be
P(n=1) is given by
Hence, our required probability is 0.2599.
a. Approximate the number of these intervals in which exactly one car arrives
Number of these intervals in which exactly one car arrives is given by
We will find the traffic flow q such that
b. Estimate the percentage of time headways that will be 14 seconds or greater.
so, it becomes,
Hence, a) 4.6798, and b) 19.8%.
