Let t, h, b represent the weighs of tail, head, and body, respectively.
t = 4 . . . . given
h = t + b/2 . . . . the head weighs as much as the tail and half the body
b/2 = h + t . . . . half the body weighs as much as the head and tail
_____
Substituting for b/2 in the second equation using the expression in the third equation, we have
... h = t + (h + t)
Subtracting h from both sides gives
... 0 = 2t . . . . . . in contradiction to the initial statement about tail weight.
Conclusion: there's no solution to the problem given here.
650 * 3456 = 2,246,400 is the answer.
Answer:
Step-by-step explanation:
The formula relating distance (d), speed (s), and time (t) is
d = st
1. Calculate the distance
d = 269 s × 4.6 m·s⁻¹ = 1240 m
2.Calculate the track radius
The distance travelled is the circumference of a circle
Answer:
21022.
Step-by-step explanation:
Find the prime factors of 10508:
2 ) 10508
2 ) 5254
37 ) 2627
71.
50208 = 2*2*37*71.
Now there is no integer value for a that would fit (a+ 1)(a - 5) = 10508 .
But we could try multiplying the LCM by 2:-
= 21016 = 2*2*2*37*71.
= 2*2*37 multiplied by 2 * 71
= 148 * 142.
That looks promising!!
a - 5 = 142 and
a + 1 = 148
This gives 2a - 4 = 290
2a = 294
a = 147.
So substituting a = 147 into a^2 - 4a + 1 we get:
= 21022.
