Find the measure of angle AOB
2 answers:
Answer:
101°
Step-by-step explanation:
20 + 25 = 45
3+2 = 5
5x + 45 = 180
Subtract 45 from 45 and 180 (both sides)
5x = 135
Divide 5x and 135 (both sides) by 5, to finally get..
x=27
3 x 27 + 20 = 101
2 x 27 + 25 = 79
Angle B.O.C = 79
Angle A.O.B = 101
See the diagram attachment I made down below.
Note:
See the diagram attachment down below. Pls, notify me if my answer is correct, hope this helps, and have a wonderful rest of your day.
<em>- kiniwih426</em>
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Question:
Points (−6, 3) and (−6, −3) on the coordinate grid below show the positions of two dogs at a park.There is a point at (−6, 3) labeled Dog 1. There is a point at (−6, −3) labeled Dog 2.
Which statement best describes the relationship between the positions of the two players?
A.Dog 1's position is Dog 2's position reflected across the y-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.
B.Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.
C.Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the x-coordinates of Dog 1 and Dog 2 are different.
D. Dog 1's position is Dog 2's position reflected across the y-axis; only the signs of the x-coordinates of Dog 1 and Dog 2 are different.
Answer:
Option B: Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.
Explanation:
The position of the Dog 1 is (−6, 3).
The position of the Dog 2 is (−6, -3).
From the graph, we can see that the image of Dog 1 is reflected over x-axis. Because to reflect an image over x-axis, the signs of y-coordinate must be changed.
Hence, Option B is correct.
Thus, Dog 1's position is Dog 2's position reflected across the x-axis; only the signs of the y-coordinates of Dog 1 and Dog 2 are different.
Answer:
Ix = Iy =
Radius of gyration x = y =
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is . Moment of inertia of quarter disk about its perpendicular is
.
Now using perpendicular axis theorem, Ix = Iy = =
.
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
The answer is 6.75, I hope this helped
