Find the critical point of the function f(x) = x^2 - 2x + 7.

1 answer:

7 0

The critical points are where the slope is 0
take the derivitive
f'(x)=2x-2

find where it equals 0
0=2x-2
2=2x
1=x
at x=1
sub that back into original function to find the y value of the critical point
f(1)=1^2-2(1)+7
f(1)=1-2+7
f(1)=-1+7
f(1)=6

the point is (1,6)
D is answer

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answer I credits: ChiKesselman solved it