Step-by-step explanation:
1. The equation graph is a parabola, so the maximum height will be the vertex of the parabola. You can find the vertex coordinate t using the formula:
t = -b/2a
t = -18/2•(-4.9)
t = -18/-9.8
t = 1.84 seconds
2. The height of the ground is 0, so the balls hit the ground when the equation result is 0:
0 = -4.9t²+18t+10
Now you solve it using Bhaskara:
Δ = b² -4ac
Δ = 18² -4•(-4.9)•10
Δ = 520
t = (-b ±√Δ)/2a
t = (-18 ± √520)/2•(-4.9)
t1 = (-18 - 20.8)/-9.8
t1 = 3.96 seconds
t2 = (-18 +20.8)/-9.8
t2 = -0.28
Doesn't exist negative time, so we pick the first value found, t = 3.96 seconds
3. Now you just need to put 3 in place of t to find the result:
h = -4.9•3² +18•3 +10
h = -4.9•9 + 54 + 10
h = -44.1 + 64
h = 19.9 meters
4. You just need to put 1 in place of t to find the height:
h = -4.9•1²+12
h = -4.9+12
h = 7.1 meters
Answer:
(16/3,-4)
Step-by-step explanation:
- y=-3/4x & y=3/2x -12
- then solve for x which means -3/4x=3/2x-12
- then the value of x=16/3
- put the x value in one equation
- y=3/4(16/3)
- then the value of y=-4
Find the length of one side.
V = s^3
s = cube root of V
V = 729
s = cube root 729
s = 9
Put this into your calculator as 729^0.333333333
It should bring back 9 or 8.999999 something which means 9.
Net
The net is shown below. You will have to do the labeling. But I can tell you what you should label each face as?
Area of one face = s^2
s = 9
Area of one face = 9*9
Area of one face = 81
So when you draw this, each face should be labeled with 81.
It should have it's units (ft^2) if your marker is picky.
Part C
There are 6 sides.
1 side has an area of 81 ft^2
6 sides have an area of 6*81 = 486 ft^2
Answer:
10 hours
Step-by-step explanation:
290 divided by 29 = 10
check to see if its correct 29 multiple by 10 is 290
There you go here’s the graph
