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EastWind [94]
3 years ago
9

What’s 2 plus 2 plus four plus eight plus six

Mathematics
2 answers:
Anastaziya [24]3 years ago
5 0

Answer:

22

Step-by-step explanation:

2+2+4+8+6=22

Anvisha [2.4K]3 years ago
5 0
Two plus two plus four plus eight plus six is twenty tow
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A cable is made up of four wires. The breaking strength of each wire is a normally distributed random variable with mean 10 kN a
Bas_tet [7]

Answer:

a) μ =35.858KN

b) median cable strength =36.06KN

Step-by-step explanation:

Let X1, X2, X3, X4 represent the strength of the 4 wires.

We can find the median of the cable strength in minitab as:

Stat - Basic statistics- Display descriptive statistics-variable (C5) -statistics(median) - ok

Median cable strength is 36.06 KN

Therefore the estimate of the mean strength of the cable is 35.858 KN, and the estimate of the median cable strength is 36.06 KN.

6 0
3 years ago
Find the length of arc AB
Alexeev081 [22]

Answer:

the answer is 4pi or 12.56637061

Step-by-step explanation:

the arc length equals 2pi x radius ( known angle (120) / 360 which equals 4pi or 12.56637061

8 0
3 years ago
A professor of women's studies is interested in determining if stress affects the menstrual cycle. Ten women are randomly sample
BabaBlast [244]

Answer:

Null hypothesis: \mu_1 = \mu_2

Alternative hypothesis: \mu_1 \neq \mu_2

t=\frac{(20.4 -27.6)-(0)}{\sqrt{\frac{2.074^2}{5}}+\frac{2.702^2}{5}}=-4.73

df=5+5-2=8

t_{crit}=\pm 2.306

Reject H0: stress affects the menstrual cycle

Step-by-step explanation:

The statistic is given by the following formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{s^2_2}{n_2}}

Where t follows a t distribution with n_1+n_2 -2 degrees of freedom  

The system of hypothesis on this case are:

Null hypothesis: \mu_1 = \mu_2

Alternative hypothesis: \mu_1 \neq \mu_2

Or equivalently:

Null hypothesis: \mu_1 - \mu_2 = 0

Alternative hypothesis: \mu_1 -\mu_2 \neq 0

Our notation on this case :

n_1 =5 represent the sample size for group 1

n_2 =2 represent the sample size for group 2

Tha data given is:

Group 1 (High stress) : 20,23,18,19,22

Group 2 (Relatively stress free): 26,31,25,26,30

We can calculate the sample mean and the sample deviation with the following formulas:

\bar X =\frac{\sum_{i=1}^n x_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}

\bar X_1 =20.4 represent the sample mean for the group 1

\bar X_2 =27.6 represent the sample mean for the group 2

s_1=2.074 represent the sample standard deviation for group 1

s_2=2.702 represent the sample standard deviation for group 2

And now we can calculate the statistic:

t=\frac{(20.4 -27.6)-(0)}{\sqrt{\frac{2.074^2}{5}}+\frac{2.702^2}{5}}=-4.73

Now we can calculate the degrees of freedom given by:

df=5+5-2=8

Now we can calculate the critical value since the confidence is 95% the value for the significance would be \alpha=1-0.95=0.05 and the value for \alpha/2 =0.025 and if we find a critical value on th t distribution with 8 degrees of freedom that accumulates 0.025 of the area on each tail we got t_{crit}=\pm 2.306

Since our calculated value is lower than the critical value, we have enough evidence to reject the null hypothesis. And makes sense say that the difference between the two means are different at 5% of significance.

Reject H0: stress affects the menstrual cycle

5 0
3 years ago
Enter the equation of the following using line in slope-intercept form.
pickupchik [31]

Answer:

?

Step-by-step explanation:

5 0
3 years ago
How do you solve angle abc if angle ab is 63 and angle bc is 42 please help!!!
Lilit [14]
<span>The answer is 105 because to solve <ABC you add up the 2 angles inside of <ABC and that would be 62+43=105.

-Hope this helps.

</span>
7 0
3 years ago
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