Answer:
30 mph
Step-by-step explanation:
Let d = distance (in miles)
Let t = time (in hours)
Let v = average speed driving <u>to</u> the airport (in mph)
⇒ v + 15 = average speed driving <u>from</u> the airport (in mph)
Using: distance = speed x time

Create two equations for the journey to and from the airport, given that the distance one way is 18 miles:

We are told that the total driving time is 1 hour, so the sum of these expressions equals 1 hour:

Now all we have to do is solve the equation for v:







As v is positive, v = 30 only
So the average speed driving to the airport was 30 mph
(and the average speed driving from the airport was 45 mph)
Answer:
-3/10
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-6-(-9))/(-3-7)
m=(-6+9)/-10
m=3/-10
m=-3/10
Answer: 8 3/4
Step-by-step explanation:
3x(4x-5+3); where x is 1/2
Substitute the value 1/2 with x
3 1/2 (4 1/2 - 5+3)
7/2 (9/2 -2)
7/2 (5/2)
35/4 = 8 3/4