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2 years ago

12

Is adding a negative always like taking away a positive ?

1 answer:

Yuki888 [10]2 years ago

3 0

Well, to word it more easily, adding a negative is just subtracting.
Here are some examples to help:

10 - 5 = 5. right? so...
10 + (-5) = 5.

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1 + 5sin^2x= 7sin^2x solve trig equation. Can you show me how to solve this trig equation?

pantera1 [17]

Answer: $x = \frac{\pi}{4}\pm k\frac{\pi}{2}\,\,\,\,\,\,k=\{0,1,2,...\}$

Step by step:

$1 + 5\sin^2x= 7\sin^2x\\\sin^2 x\rightarrow z\\1 + 5z = 7z\\2z = 1\\z = \frac{1}{2}\implies \sin^2 x = \frac{1}{2}\\|\sin x| = \frac{1}{\sqrt{2}}\\\sin x = \pm\frac{1}{\sqrt{2}}=\pm\frac{\sqrt{2}}{2}\\\implies x = \frac{\pi}{4}\pm k\frac{\pi}{2}\,\,\,\,\,\,k=\{0,1,2,...\}$

(Used a table of common angles)

8 0

3 years ago

Integration of the following function

DerKrebs [107]

Answer: None of the above

Step-by-step explanation:

Given

$\frac{\mathrm{d} \bar{c}}{\mathrm{d} x}=-6x^{-2}+\frac{1}{6}$

$d\bar{c}=\left ( -6x^{-2}+\frac{1}{6}\right )dx$

Now, integrating both sides

$\int d\bar{c}=\int \left ( -6x^{-2}+\frac{1}{6}\right )dx$

$\bar{c}=-6\frac{x^{-2+1}}{-2+1}+\frac{1}{6}x+k_1$

$\bar{c}=6x^{-1}+\frac{1}{6}x+k_1$

6 0

3 years ago

Ratio equivalent to 1:3

Margaret [11]

2:6

3:9

4:12

These are all equivilant

4 0

3 years ago

Read 2 more answers

List the subsets of the set { dog,cat,rabbit}

ser-zykov [4K]

Answer: so dog goes to cat, dog goes to rabbit and cat goes to rabbit I think

Step-by-step explanation:

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2 years ago

Look at the expression:<br>42x-56y<br>Is it equivalent to<br>7(6x-8y)?<br><br>Yes Or No

Katarina [22]

Answer:yes it is

Step-by-step explanation:

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2 years ago